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castortr0y [4]
3 years ago
10

Determine the measure of angle uvs

Mathematics
2 answers:
castortr0y [4]3 years ago
5 0

Answer:

m\angle UVS=39^o

Step-by-step explanation:

We have been given an image of a circle and we are asked to find the measure of angle UVS.

We can see that angle UVS is an inscribed angle of our given circle and it intercepts to arc US.

Since we know that the measure of inscribed angle is half the measure of its intercepted arc.

m\angle UVS=\frac{1}{2}\times \text{Measure of arc US}

m\angle UVS=\frac{1}{2}\times 78^o

m\angle UVS=39^o

Therefore, the measure of angle UVS is 39 degrees.

Korolek [52]3 years ago
3 0
The angle measure is 78/2 degrees. that would simplify down to 39 degrees. I don't remember the theroem but I do know that the angle is half the side length angle measure
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The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
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Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

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8 0
3 years ago
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5 0
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What is the answer to this
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