Answer:
y = 4x - 6
Step-by-step explanation:
12x - 3y = 18 is in standard form. We need to convert it to slope-intercept form, which looks like y = mx + b, with m being the slope and b being the y-intercept.
We know that 12x has to do with our slope, and 18 is our y-intercept. We need to put those on the right side of the equation so that we can isolate y on the left side:
12x - 3y = 18
Subtract 12x from both sides.
-3y = -12x + 18
Now, we can divide both sides by -3 to get y by itself.
y = 4x - 6
And that looks like slope-intercept form (y = mx + b).
Hopefully this was helpful! If you have more questions, let me know. :)
I am not sure what the answer is but covert them into a decimal and then divide it
Answer:
B. Not a function
Step-by-step explanation:
<h2>Hello!</h2>
The answer is:
C. Cosine is negative in Quadrant III
<h2>
Why?</h2>
Let's discard each given option in order to find the correct:
A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).
B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.
C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.
D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)
Have a nice day!
The point-slope form the line which has the value of slope -5 and contains a point as A(2,-1) is (y+1)=-5(x-2).
<h3>What is point slope form?</h3>
The point slope form of a line is the expression of line which has a specified slope and passes through a point.
The point slope form is givne as,
(y-y₁)=m(x-x₁)
Here, m is the slope of the line, x₁ is the x coordinate of the point by which line passes and y₁ is the y coordinate of the same point.
The slope of a line is -5. This line contains the point A (2,-1). Thus, the point slope form is,
(y-y₁)=m(x-x₁)
(y-(-1))=-5(x-2)
(y+1)=-5(x-2)
Thus, the point-slope form the line which has the value of slope -5 and contains a point as A(2,-1) is (y+1)=-5(x-2).
Learn more about the point slope form here;
brainly.com/question/6497976
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