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abruzzese [7]
2 years ago
10

3.4 For each of the following elements, locate it in the Periodic Table, and indicate whether it is a metal, metalloid, or non-m

etal. (3) 4.4.1 Germanium (Ge) 4.4.2 Selenium (Se) 4.4.3 Beryllium (Be)
​
Chemistry
1 answer:
12345 [234]2 years ago
6 0

According to its location in the periodic table:

  • Ge: Period 4, Group 14. Metalloid.
  • Se: Period 4, Group 6, Non-metal.
  • Be: Period 2, Group 2, Metal.

<h3>What is a periodic table?</h3>

It is a table in which elements are ordered in Groups (columns) and Periods (rows).

According to their ubication and properties they can be classified in:

  • Metals: occupy the left and center of the table.
  • Metalloids: occupy the right of the table (dark green in the attached table).
  • Non-metals: occupy the right of the table (yellow and light green in the attached image).

Let's locate and classify the following elements:

  • Germanium: Period 4, Group 14. Metalloid.
  • Selenium: Period 4, Group 6, Non-metal.
  • Beryllium: Period 2, Group 2, Metal.

Learn more about the periodic table here: brainly.com/question/14514242

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If its a true or false statement . the answer is true 
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(a) The original value of the reaction quotient, Qc, for the reaction of H2(g) and I2(g) to form HI(g) (before any reactions tak
Taya2010 [7]

Answer:

Here's what I get  

Explanation:

Assume the initial concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.

We must calculate the initial concentration of HI.

1. We will need a chemical equation with concentrations, so let's gather all the information in one place.

                   H₂ +    I₂    ⇌ 2HI

I/mol·L⁻¹:    0.30   0.15         x

2. Calculate the concentration of HI

Q_{\text{c}} = \dfrac{\text{[HI]}^{2}} {\text{[H$_{2}$][I$_{2}$]}} =\dfrac{x^{2}}{0.30 \times 0.15} =  5.56\\\\x^{2} = 0.30 \times 0.15 \times 5.56 = 0.250\\x = \sqrt{0.250} = \textbf{0.50 mol/L}\\\text{The initial concentration of HI is $\large \boxed{\textbf{0.50 mol/L}}$}

3. Plot the initial points

The graph below shows the initial concentrations plotted on the vertical axis.

 

7 0
3 years ago
If 13.8 moles of carbon (c), with a density of 2.26 g/ml, are needed for a chemical reaction, how many milliliters of carbon are
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13.8 moles of carbon = 12 g/mol*13.8 or 165.6 grams

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I hope this helps!!!!


8 0
3 years ago
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We can also use the activity series to predict reactions between a metal and an acid. what are the products of the reaction fe(s
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Answer;

FeSO4 (aq) + H2 (g)

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The reaction between iron and dilute sulfuric acid gives a salt and hydrogen gas. (iron (ii) sulfate and hydrogen gas).

The equation for the reaction is;

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8 0
4 years ago
The cavity within a copper [β = 51 × 10-6 (C°)-1] sphere has a volume of 1.220 × 10-3 m3. Into this cavity is placed 1.100 × 10-
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Answer:

Δ should be 0.1009

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with v0 = the initial volume

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((1.22*10^-3)-(1.1*10^-3))/((1240*10^-6)-(51*10^-6)) = Δ

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Δ should be 0.1009

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