The energy needed to warm water be 55 Celsius would be
Q=m*c* Delta T
We are given the following data
Q=526
m=7.4
T=17C= 526/17*7.4
Putting in the equation we get
Q=mc DeltaT
<span>Q=7.4x55x526/17x7.4
=55x526/17
</span>
=1701.64 C
Answer:
The molarity is 0.203 M
Explanation:
Using the formula C(oxi) x V(oxi) / [C(red) x V(red)] = N(oxi) / N(red)
Where oxi and red means reducing agent and oxidising agent respectively.
C = Concentration, V = Volume and N = number of moles.
C(oxi) = 0.5 M
V(oxi) = mL
C(red) = ?
V(red) = 30mL
Equation of reaction = 2K2S2O3 + KI3 = K2S4O6 + 3KI
so N(red) = 1 , N(oxi) = 2
from the equation above,
C(red) = 0.5 x 25 x 1 / (2 x 30)
= 0.203 M.
C2H2 is the right answer I believe
Answer:
40.7 kJ
Step-by-step explanation:
The formula for the heat, q, needed to evaporate a liquid is
q = mΔHvap
<em>Data: </em>
m = 180 g
ΔHvap = 2260 J/g
<em>Calculation:
</em>
q = 180 g × 2260 /1
q = 40 700 J = 40.7 kJ
