m∠B = 33° is the answer.
<u>Step-by-step explanation:</u>
If two triangles ΔABC and ΔMOP are similar, then their corresponding angles are congruent.
In any triangle, sum of the measure of the angles add up to 180°.
∠A+ ∠B+ ∠C = 180°
∠A ≅ ∠M
∠B ≅ ∠O
∠C ≅ ∠P
So we can add as,
∠A + ∠B+ ∠P = 180°
45° + ∠B + 102° = 180°
∠B + 147° = 180°
∠B = 180° - 147° = 33°
Answer:
B. Line A intersects line B at the point (-2,2)
Step-by-step explanation:
y = mx + b
m₁ = 2
-2 = 2 x (-4) + b₁
b₁ = 6
y₁ = 2x₁ + 6 : line₁
point (-2 , 2) : 2 x (-2) + 6 = 2
(-2 , 2) is on line₁
m₂ = (-4 -4 ) / (10 - (-6)) = -8 / 16 = - 1/2
line₂ : (-6 , 4) (10 , -4)
4 = - 1/2 x (-6) + b₂
b₂ = 1
y₂ = -1/2 x + 1 : line₂
point (-2 , 2) -1/2 x (-2) + 1 = 2
prove (-2 , 2) is on line₂ too.
Do you have a picture of the problem. I am a visual learner? msg me if you need any other help.
65.98 because of it I have no clue how much you want me and you to get me some of my stuff I need you I know I have a good idea of that but I’m still in a little while
Volume of sand = Volume of sand in the cylindrical pi
1/3 πr^2h = πr^2h
1/3 x 3.14 x 3^2 x 6 = 3.14 x 6^2 x h
6h = 3
h = 3/6 = 1/2 ft
The height of the sand in the pit is 0.5 ft.