Ap chem, please help with number 31!!
1 answer:
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<u>Answer:</u> The concentration of chloride ions in the solution obtained is 0.674 M
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
.....(1)
- <u>For KCl:</u>
Molarity of KCl solution = 0.675 M
Volume of solution = 297 mL
Putting values in equation 1, we get:
1 mole of KCl produces 1 mole of chloride ions and 1 mole of potassium ion
Moles of chloride ions in KCl = 0.200 moles
- <u>For magnesium chloride:</u>
Molarity of magnesium chloride solution = 0.338 M
Volume of solution = 664 mL
Putting values in equation 1, we get:
1 mole of magnesium chloride produces 2 moles of chloride ions and 1 mole of magnesium ion
Moles of chloride ions in magnesium chloride =
Calculating the chloride ion concentration, we use equation 1:
Total moles of chloride ions in the solution = (0.200 + 0.448) moles = 0.648 moles
Total volume of the solution = (297 + 664) mL = 961 mL
Putting values in equation 1, we get:
Hence, the concentration of chloride ions in the solution obtained is 0.674 M