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RoseWind [281]
2 years ago
6

What volume of air is needed to burn completely 100cm of propane?

Chemistry
1 answer:
Evgesh-ka [11]2 years ago
5 0

Answer:

See below

Explanation:

propane mole weight = 44 gm / mole

100 gm / 44 gm / mole = 2.27 moles

From the equation, 5 times as many moles of OXYGEN (O2)are required

   = 11.36 moles of oxygen

           at <u>STP</u> this is 254.55  liters of O2 (because 22.4 L = one mole) and

Using oxygen as 21 percent of air means that

      .21 x = 254.55 =       x = <u>1212.12 liters of air required </u>

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Andreas93 [3]
If you are provided with Cation and an Anion with different oxidation states, then there ratio in the formula unit is adjusted as such that the oxidation number of one ion is set the coefficient of other ion and vice versa,

Example:
               Let suppose you are provided with A⁺² and B⁻¹, so multiply A by 1 and B by 2 as follow,
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In statement we are given with Co⁺³ and SO₄⁻², so multiply Co⁺³ by 2 and SO₄⁻² by 3, hence,

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