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Complete Question:
A certain ionic compound X has a solubility in water of .765g/ml at 5 degrees C. Calculate the mass of X that's dissolved in 3 L of a saturated solution of X in the water at this temp. Be sure your answer has the correct unit symbol and significant digits.
Answer:
2.29 kg
Explanation:
A saturated solution is a solution that has the maximum amount of solute diluted at it, so if more solute is added, it will precipitate. The solutions can also be unsaturated (when more solute can be dissolved) or supersaturated (when there is more solute dissolved than the maximum. It's a very unstable solution).
The saturation is measured by the solubility, which indicates how much mass of the solute can be added to a certain volume of the solvent. So, the solubility (S) is the mass (m) divided by the volume (V).
For a solution with 3 L = 3000 mL,
S = m/V
0.765 = m/3000
m = 3000 * 0.765
m = 2295 g
m = 2.29 kg
