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taurus [48]
2 years ago
14

IF anyone didn't do this E D G E N U I T Y thing here you guys go pass it around to people that need help this is what it is cal

led Quiz Ionic Bonding got 100%
1) which of these best describes an ionic bond?
correct answer- C) A force that holds two oppositely charged ions together.

2) Which pair of ions can form an ionic bond with each other and why?
correct answer- D) Li^+ and Br^ - ; They have unlike charges.

3) The table lists the lattice energies of some compounds.
Which statement about crystal lattice energy is best supported by the information in the table?
correct answer- A) The lattice energy increases as cations get smaller, as shown by LiF and KF.

4) Which statement is true about ionic compounds?
correct answer- C) They are made up of particles that are arranged in a repeating pattern.

5) Each model shows bonding between a pair of atoms.
Which statement best explains how the models differ?
correct answer- C) Model A shows the sharing of electrons, and model B shows the formation of ions.

6) Which property best indicates that a compound contains an ionic bond?
correct answer- D) It conducts electricity when molten.

7) Which of the following can easily form an ionic bond with a cation?
correct answer- D) PO43-

8) Which statement is true about a polyatomic ion?
correct answer- C) It is made of atoms that are covalently bonded together.

9) Which statement indicates that a substance may be an ionic compound?
correct answer- D) It is made up of a crystal lattice.

10) Which statement best describes how an ionic bond forms?
correct answer- A) The transfer of electrons forms strong bonds between ions.
Chemistry
1 answer:
SashulF [63]2 years ago
5 0

Answer:

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Explanation:

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6 0
3 years ago
Select the answer which shows the correct order, slowest to fastest, of the relative rate of diffusion of the gases.
IrinaK [193]

Diffusion is the process of a substance spreading out to evenly fill its container or environment. Rate of diffusion of a gas is inversely proportional to the molar mass of the gas.

Rate of diffusion \propto \frac{1}{Molar mass}

Lighter(lower) the molar mass of the gas , faster will be its rate of diffusion and heavier (higher) the molar mass of the gas , slower will be its rate of diffusion.

We have to arrange the given gases from slowest rate of diffusion to fastest rate of diffusion that means we need to arrange gases from higher molar mass to lower molar mass.

Molar mass of given gases are :

Cl = 35.5 g/mol

Xe = 131.29 g/mol

He = 4.00 g/mol

N = 14.00 g/mol

So correct order for slowest rate of diffusion (highest molar mass) to fastest rate of diffusion (lowest molar mass) is :

Xe , Cl , N , He

Xe having the highest molar mass will have the slowest rate of diffusion and He with lowest molar mass will have the fastest rate of diffusion, so option 'c' is correct.

Note : Slowest rate of diffusion = High Molar Mass

Fastest rate of diffusion = Low Molar Mass



7 0
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A student must make a 3 m acid solution using a 5 m acid solution. which of these is the safest way to make the solution?
weqwewe [10]
The motivation to abstain from adding water to concentrated acids is that, with a few acids, amid weakening, a considerable measure of warmth is discharged, by adding the corrosive to the water, the generally extensive measure of water will retain the warmth. On the off chance that you added water to concentrated corrosive when you initially beginning pouring the water, it could get sufficiently hot for the little measure of water that was filled all of a sudden bubble and splatter corrosive on you. Concentrated sulfuric corrosive is most famous for doing this, not all acids get that hot on weakening, but rather in the event that you make a propensity for continually adding the corrosive to water for every one of them, you can't turn out badly.
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A student was trying to obtain lithium by electrolysis of aqueous lithium chloride. Was he successful?
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The student was not successful.

Consider the standard reduction potentials.

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To reduce Li⁺ to Li, the student must apply 3.04 V.

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Thus, the student will get H₂ instead of Li.

6 0
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