Answer:
3.568 g of H₂O
Solution:
The Balance Chemical Equation is as follow,
2 H₂ + O₂ → 2 H₂O
Step 1: Calculate the Limiting Reagent,
According to Balance equation,
4.04 g (2 mol) H₂ reacts with = 32 g (1 mol) of O₂
So,
0.40 g of H₂ will react with = X g of O₂
Solving for X,
X = (0.40 g × 32 g) ÷ 4.04 g
X = 3.17 g of O₂
It means 0.4 g of H₂ requires 3.17 g of O₂, while we are provided with 3.2 g of O₂ which is in excess. Therefore, H₂ is the limiting reagent and will control the yield of products.
Step 2: Calculate amount of Water produced,
According to equation,
4.04 g (2 mol) of H₂ produces = 36.04 g (2 mol) of H₂O
So,
0.40 g of H₂ will produce = X moles of H₂O
Solving for X,
X = (0.40 g × 36.04 mol) ÷ 4.04 g
X = 3.568 g of H₂O
Uranium-232 will remain 11.72 g
<h3>Further explanation
</h3>
The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually radioactive elements have an unstable atomic nucleus.
The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles
General formulas used in decay:
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t 1/2 = half-life = 68.8 years
T = duration of decay = 344 years
No= initial sample = 375 g
Uranium-232 remain :
Answer:
I think it is B
Explanation:
Both prokaryotes and eukaryotes have all of those things except for organelles, which only eukaryotes have (also prokaryotes are smaller not eukaryotes)
Answer:
0.574moles
Explanation:
Using the general gas equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (Litres)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (Kelvin)
According to the information provided in the question;
- Volume (V) = 12400mL = 12400/1000 = 12.4L
- Pressure (P) = 890mmHg = 890/760 = 1.17atm
- Temperature (T) = 35°C = 35 + 273 = 308K
Hence, using PV = nRT
n = PV/RT
n = 1.17 × 12.4 ÷ 0.0821 × 308
n = 14.508 ÷ 25.287
n = 0.574moles
Therefore, the number of moles of argon gas in the cylinder is 0.574moles
