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Xelga [282]
3 years ago
8

Technician A says that the brake pedal should be depressed with as much force as possible during the normal bleeding procedure.

Technician B says that the brake pedal should be pumped rapidly during this manual bleeding procedure to force the air down toward the bleeder valve(s). Which technician is correct?
A. Technician A only
B. Technician B only
C. Both technician A and B
D. Neither technician A and B
Physics
1 answer:
Firlakuza [10]3 years ago
4 0

Answer:

i think its neither technician

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The weight of a girl with the mass of 40.0kg is ?
Allushta [10]

Answer:

392 Newtons

Explanation:

In order to find the weight, you have to multiply the mass by the gravitation constant (9.8), which gives us 40.0 * 9.8 = 392 Newtons.

4 0
3 years ago
Select all that apply.
lyudmila [28]
B and d r both answers.
6 0
3 years ago
Read 2 more answers
The x component of vector is 8.7 units, and its y component is -6.5 units. The magnitude of is closest to
irina1246 [14]

Answer:

F = 10.86 units

Explanation:

The magnitude of a vector in terms of the magnitude of its rectangular components is given by the following formula:

F = √(Fₓ² + Fy²)

where,

F = Magnitude of the Vector = ?

Fₓ = magnitude of the x-component of vector = 8.7 units

Fy = magnitude of y component of vector = - 6.5 units

Therefore, using these values in the equation, we get:

F = √[(8.7 units)² + (- 6.5 units)²]

F = √(117.94 units²)

<u>F = 10.86 units</u>

5 0
3 years ago
Rank the wavelengths of the following quantum particles from the largest to the smallest. If any have equal wavelengths, display
goldfiish [28.3K]

The wavelengths of the following quantum particles from the largest to the smallest is (d) > (a) = (e) > (b) > (c)

  • De Broglie proposed that because light has both wave and particle properties, matter exhibits both wave and particle properties. This property has been explained as the dual behavior of matter.
  • From his observations, de Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship.

De Broglie's relationship is given by  \lambda=\frac{h}{mv} .

This can be written as \lambda=\frac{h}{p}  .....(1) where λ  is known as de Broglie wavelength and p is momentum , h = Plank’s constant .

As we know that mass of proton is greater than electron and photon .

(a)For photon , the momentum is given by p=\frac{E}{c}     ...(2)  where c is the speed is the speed of light .

Putting E = 3eV in equation (2) , we get

              p=\frac{3\times 1.6\times10^-^1^9}{3\times 10^8} \\p=1.6\times10^-^2^7Js/m

Putting this value of p in equation (1) , we get

  \lambda=\frac{6.62\times10^{-34}}{1.6\times10^{-27}}\\\lambda=4.13\times10^{-7}

(b) As we know that  kinetic energy is given by

         K.E=\frac{1}{2} mv^2\\\\2K.E = mv^2\\2K.E\times m = m^2v^2\\2K.E\times m = (mv)^2\\2K.E\times m = p^2\\\\\sqrt{2K.E\times m }=p      ...(3)

Where mass of electron is 9.1\times10^-^3^1 kg .

Putting K.E = 3eV in equation (3) , we get

    \sqrt{2K.E\times m }=p\\p=\sqrt{2\times3\times1.6\times10^{-19} \times 9.31\times10^{-31} }\\p=\sqrt{89.376\times10^{-50}} \\p=9.45\times10^{-25}Js/m

Putting this value of p in equation (1) , we get

\lambda=\frac{6.62\times10^{-34}}{9.45\times10^{-25}}\\\lambda=0.7005\times10^{-9}

(c) Putting m=1.67\times10^{-27}kg and K.E = 3eV in equation (3) , we get

     \sqrt{2K.E\times m }=p\\p=\sqrt{2\times3\times1.6\times10^{-19} \times 1.67\times10^{-27} }\\p=\sqrt{16.032\times10^{-46}} \\p=4.003\times10^{-23}Js/m

Putting this value of p in equation (1) , we get

\lambda=\frac{6.62\times10^{-34}}{4.003\times10^{-23}}\\\lambda=1.65\times10^{-11}

(d) Putting E = 0.3eV in equation (2) , we get

   p=\frac{0.3\times 1.6\times10^-^1^9}{3\times 10^8} \\p=1.6\times10^-^2^8Js/m

Putting this value of p in equation (1) , we get

\lambda=\frac{6.62\times10^{-34}}{1.6\times10^{-28}}\\\lambda=4.13\times10^{-6}

(e) Putting p=3eV/c in equation (1) , we get

    \lambda=\frac{6.62\times10^{-34}\\\times3\times10^8}{3\times1.6\times10^{-19}}\\\lambda=4.13\times10^{-7}

On comparing the wavelength order should be (d) > (a) = (e) > (b) > (c) .

Learn more about de brogile here :

brainly.com/question/28165547

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6 0
2 years ago
An airplane is seller rates down a runway at 3.10 M/S squared 441.5 seconds from rest until finally left off the ground ,what is
sineoko [7]

Answer:

302129m

Explanation:

Using s= ut + 1/2at²

But u= 0

So

S= 1/2(3.1)(441.5)²

=302129m

6 0
4 years ago
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