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3 years ago

Henry can write 5 pages of his novel in 3 hours. At this rate, how many pages can Henry write in 8 hours?

Mathematics

1 answer:

Anna007 [38]3 years ago

8 0

Step-by-step explanation:

3 hours =5 pages

8 hours =x

Cross multiplying

3x=5×8

3x=40

Dividing both sides by 3

3x/3=40/3

x=13.33

To the nearest whole number Henry will write 13 pages in 8 hours

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A group of friends were working on a student film that had a budget of $700. They used 42% of their budget on equipment. How muc

goldfiish [28.3K]

Answer:

294

Step-by-step explanation:

100%-> 700

42%->294

5 0

2 years ago

Help I’m almost out of time

VladimirAG [237]

Answer: First option.

Step-by-step explanation:

You can idenfity in the figure that $\angle FCE$ is formed by two secants that intersect outside of the given circle.

It is important to remember that, by definition:

$Angle\ formed\ by\ two\ Secants=\frac{1}{2}( Difference\ of\ intercepted\ Arcs)$

Knowing this, you can set up the following equation:

$m\angle FCE=\frac{1}{2}(BD-FE)$

Therefore, you must substitute values into the equation and then evaluate, in order to find the measure of the angle $\angle FCE$ .

This is:

$m\angle FCE=\frac{1}{2}(112\°-38\°)\\\\m\angle FCE=37\°$

6 0

3 years ago

What is the equation written in vertex form of a parabola with a vertex of (–1, 8) that passes through (1, 0)?

Archy [21]

Answer:

y = -2(x + 1)^2 + 8

Step-by-step explanation:

The equation of a parabola can be written in the form;

y = a(x-h)^2 + k

where a is the multiplier (h,k) is the vertex

so h = -1 and k = 8

Plug in these values

y = a(x + 1)^2 + 8

So to get the value of a, we use the point where the parabola passes through which is the point (1,0)

Simply substitute the values of x and y

0 = a(1 + 1)^2 + 8

0 = a(2)^2 + 8

-8 = 4a

a = -8/4

a = -2

So therefore the equation of the parabola is ;

y = -2(x + 1)^2 + 8

7 0

3 years ago

1.Encuentra la ecuación de la circunferencia que tiene como ecuación ordinaria (x-4)² + (y+5)²= 25 2- encuentra la ecuación gene

rodikova [14]

Responder:

1) x² + y²-8x + 10y + 16 = 0

2) x² + y² + x + 18y + 33 = 0

Explicación paso a paso:

A partir de la pregunta, debemos expresar la ecuación en la forma estándar de un círculo expresado como;

x² + y² + 2gx + 2fy + c = 0 donde;

(-g, -f) es el centro.

1) Para la ecuación (x-4) ² + (y + 5) ² = 25

Expande el paréntesis;

(x-4) ² + (y + 5) ² = 25

x²-8x + 16 + y² + 10x + 25 = 25

x²-8x + 16 + y² + 10y + 25-25 = 0

Recopile términos similares;

x² + y²-8x + 10y + 16 + 0 = 0

x² + y²-8x + 10y + 16 = 0

Por lo tanto, la ecuación requerida es x² + y²-8x + 10y + 16 = 0

2) Para la expresión (x + 1) ² + (y + 9) ² = 49

x² + x + 1 + y² + 18y + 81 = 49

x² + x + 1 + y² + 18y + 81-49 = 0

Recopile términos similares;

x² + y² + x + 18y + 82-49 = 0

x² + y² + x + 18y + 33 = 0

Por tanto, la ecuación requerida es x² + y² + x + 18y + 33 = 0

4 0

2 years ago

The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source

Bezzdna [24]

Answer:

The voltage at the middle source is $(2-4\mathbf{i})\ V$

Step-by-step explanation:

Voltage Sources in Series

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

$2 + 6\mathbf{i}$

$a + b\mathbf{i}$

$2 - 5\mathbf{i}$

The sum of these voltages is:

$V_t=4+a+(6+b-5)\mathbf{i}$

Operating:

$V_t=4+a+(1+b)\mathbf{i}$

We know the total voltage is $6-3\mathbf{i}$ , thus:

$4+a+(1+b)\mathbf{i}=6-3\mathbf{i}$

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is $(2-4\mathbf{i})\ V$

5 0

2 years ago