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alex41 [277]
3 years ago
9

A secant and a tangent meet at a 90° angle outside the circle. What must be the difference between the measures of the intercept

ed arcs?
Mathematics
1 answer:
ra1l [238]3 years ago
8 0
Just took the test, correct answer 180
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* * +:) help .........
adoni [48]

1. -11     2.-3

Make sure to simplify the equation..

example: 3(2x - 7) = 6x - 21

because 3 x 2 = 6 and 3 x 7 = 21

8 0
2 years ago
The bill for dinner was $34. You left $50 to pay for the meal and tip the server. What percent of the meal did you leave as a ti
9966 [12]

Answer:

16

Step-by-step explanation:

50 - 34 = 16

6 0
3 years ago
Solve for the value of X pleassee
bulgar [2K]

Answer:

188

Step-by-step explanation:

SR and ST are equal in length so the arc SR and arc ST also have same measurement

since the perimeter of the circle is equal to 360 and arc RT is given as 64

x = (360 - 64) / 2

x = 188

3 0
3 years ago
14=2y/5 <br><br> What’s the answer
shutvik [7]
The answer is 35 ok ?
7 0
3 years ago
The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml
irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.63}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.63}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

8 0
2 years ago
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