Answer: Combustion is also known as burning, and the substance that burns is usually referred to fuel. The products of a complete combustion reaction include carbon dioxide (CO2) and water vapor (H2O).
Explanation:
Answer:
Molar ratio of the compound is 1:1 and the type of hydrate is Mono hydrate.
Explanation:
From the given,
Mass of sodium carbonate 
= 8.85 g
Loss mass 
= 1.28 g
Actual weight of sodium carbonate = 8.85 g - 1.28 g = 7.57 g
Therefore, the compound has only one water molecule.
Molecular formula of the compound is 
an name of the compound is <u>sodium carbonate mono hydrate.</u>
Hence, the type of the compound is Mono hydrate.
Answer:
b. 2.28 M
Explanation:
The reaction of neutralization of NaOH with H2SO4 is:
2NaOH + H2SO4 → Na2SO4 + 2H2O
<em>Where 2 moles of NaOH react per mole of H2SO4</em>
<em />
To solve the concentration of NaOH we need to find the moles of H2SO4. Using the chemical equation we can find the moles of NaOH that react and with the volume the molar concentration as follows:
<em>Moles H2SO4:</em>
45.7mL = 0.0457L * (0.500mol/L) = 0.02285 moles H2SO4
<em>Moles NaOH:</em>
0.02285 moles H2SO4 * (2moles NaOH / 1 mol H2SO4) = 0.0457moles NaOH
<em>Molarity NaOH:</em>
0.0457moles NaOH / 0.020L =
2.28M
Right option:
<h3>b. 2.28 M</h3>
The answer is B) dry and irregular
