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mojhsa [17]
3 years ago
6

Suppose that the pH of soil samples taken from a certain geographic region is normally distributed with a mean pH of 7 and a sta

ndard deviation of 0.10. If the pH of a randomly selected soil sample from this region is determined and equal to x, answer the following questions about it.a. What is the probability that the resulting pH is between 5.90 and 6.15?b. What is the probability that the resulting pH exceeds 6.10?c. What is the probability that the resulting pH is at most 5.95?d. What value will be exceeded by only 5% of all such pH values?
Mathematics
1 answer:
Otrada [13]3 years ago
4 0

Answer:

a) P=0

b) P=1

c) P=0

d) X=7.1645

Step-by-step explanation:

We have the pH of soil for some region being normally distributed, with mean = 7 and standard deviation of 0.10.

a) What is the probability that the resulting pH is between 5.90 and 6.15?

We calculate the z-score for this 2 values, and then compute the probability.

z_1=(X_1-\mu)/\sigma=(5.9-7.0)/0.1=-11\\\\z_2=(X_2-\mu)/\sigma=(6.15-7)/0.1=-8.5

Then the probability is

P(5.90

b) What is the probability that the resulting pH exceeds 6.10?

We repeat the previous procedure.

z=(6.10-7)/0.1=-9\\\\P(x>6.1)=P(z>-9)=1

c) What is the probability that the resulting pH is at most 5.95?

z=(5.95-7)/0.1=-10.5\\\\P(x

d. What value will be exceeded by only 5% of all such pH values?

We have to calculate the value of pH for which only 5% is expected to be higher. This can be represented as P(X>x)=0.05.

In the standard normal distribution, it happens for a z=1.645.

P(z>1.645)=0.05

Then, we can calculate the pH as:

x=\mu+z\sigma=7.0+1.645*0.1=7.0+0.1645=7.1645

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Rom4ik [11]

Answer:

a) \sqrt{61 - 24 \sqrt{5} }  =  - 4  + 3 \sqrt{5}

b)( \sqrt{ ( {c}^{2}   -  1) ({b}^{2}    -  1) } - {2 \sqrt{bc} }) (\sqrt{ ( {c}^{2}   -  1) ({b}^{2}    -  1) }  + {2 \sqrt{bc}  } )

c) \frac{ \sqrt{9 - 4 \sqrt{5} } }{2 -  \sqrt{5} }  =   - 1

Step-by-step explanation:

We want to simplify

\sqrt{61 - 24 \sqrt{5} }

Let :

\sqrt{61 - 24 \sqrt{5} }  = a - b \sqrt{5}

Square both sides of the equation:

(\sqrt{61 - 24 \sqrt{5} } )^{2}  =  ({a - b \sqrt{5} })^{2}

Expand the RHS;

61 - 24 \sqrt{5} =  {a}^{2}  - 2ab \sqrt{5}  + 5 {b}^{2}

Compare coefficients on both sides:

{a}^{2}  + 5 {b}^{2}  = 61 -  -  - (1)

- 24 =  - 2ab \\ ab = 12 \\ b =  \frac{12}{b}  -  -  -( 2)

Solve the equations simultaneously,

\frac{144}{ {b}^{2} }  + 5 {b}^{2}  = 61

5 {b}^{4}  - 61 {b}^{2}  + 144 = 0

Solve the quadratic equation in b²

{b}^{2}  = 9 \: or \:  {b}^{2}  =  \frac{16}{5}

This implies that:

b =  \pm3 \: or \: b =  \pm  \frac{4 \sqrt{5} }{5}

When b=-3,

a =  - 4

Therefore

\sqrt{61 - 24 \sqrt{5} }  =  - 4  + 3 \sqrt{5}

We want to rewrite as a product:

{b}^{2}  {c}^{2}  - 4bc -  {b}^{2}  -  {c}^{2}  + 1

as a product:

We rearrange to get:

{b}^{2}  {c}^{2}   -  {b}^{2}  -  {c}^{2}  + 1- 4bc

We factor to get:

{b}^{2} ( {c}^{2}   -  1)  -  ({c}^{2}   -  1)- 4bc

Factor again to get;

( {c}^{2}   -  1) ({b}^{2}   -  1)- 4bc

We rewrite as difference of two squares:

(\sqrt{( {c}^{2}   -  1) ({b}^{2}   -  1) })^{2} - ( {2 \sqrt{bc} })^{2}

We factor the difference of square further to get;

( \sqrt{ ( {c}^{2}   -  1) ({b}^{2}    -  1) } - {2 \sqrt{bc} }) (\sqrt{ ( {c}^{2}   -  1) ({b}^{2}    -  1) }  + {2 \sqrt{bc}  } )

c) We want to compute:

\frac{ \sqrt{9 - 4 \sqrt{5} } }{2 -  \sqrt{5} }

Let the numerator,

\sqrt{9 - 4 \sqrt{5} }  = a - b \sqrt{5}

Square both sides of the equation;

9 - 4 \sqrt{5}  =  {a}^{2}  - 2ab \sqrt{5}  + 5 {b}^{2}

Compare coefficients in both equations;

{a}^{2}  + 5 {b}^{2}  = 9 -  -  - (1)

and

- 2ab =  - 4 \\ ab = 2 \\ a =  \frac{2}{b}  -  -  -  - (2)

Put equation (2) in (1) and solve;

\frac{4}{ {b}^{2} }  + 5 {b}^{2}  = 9

5 {b}^{4}   - 9 {b}^{2}  + 4 = 0

b =  \pm1

When b=-1, a=-2

This means that:

\sqrt{9 - 4 \sqrt{5} }  =  - 2 +  \sqrt{5}

This implies that:

\frac{ \sqrt{9 - 4 \sqrt{5} } }{2 -  \sqrt{5} }  =  \frac{ - 2 +  \sqrt{5} }{2 -  \sqrt{5} }  =  \frac{ - (2 -  \sqrt{5)} }{2 -  \sqrt{5} }  =  - 1

3 0
3 years ago
Read 2 more answers
29 divide 2,949 please help lol it is for my lit sis
sattari [20]
0.009833

Or you mean 2,949 divided by 29 which is 101.6896
8 0
3 years ago
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