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Lilit [14]
3 years ago
10

What is the distance covered in 20 minutes by a train traveling 500m/m?

Physics
1 answer:
MrMuchimi3 years ago
3 0

Answer:

answer is 10km

Explanation:

use "S =Ut "

S=distance U=velocity t =time

no need to convert time into seconds as the velocity has given in meters per minute

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6–23 an automobile engine consumes fuel at a rate of 22 l/h and delivers 55 kw of power to the wheels. if the fuel has a heating
Anna007 [38]

Explanation & answer:

Given:

Fuel consumption, C = 22 L/h

Specific gravity = 0.8

output power, P  =  55 kW

heating value, H = 44,000 kJ/kg

Solution:

Calculate energy intake

E = C*P*H

= (22 L/h) / (3600 s/h) * (1000 mL/L) * (0.8 g/mL) * (44000 kJ/kg)

= (22/3600)*1000*0.8*44000 j/s

= 215111.1 j/s

Calculate output power

P = 55 kW

= 55000 j/s

Efficiency

= output / input

= P/E

=55000 / 215111.1

= 0.2557

= 25.6% to 1 decimal place.

8 0
3 years ago
if a bowling ball hits a wall a force of 6 N, the wall exerts a force of how much back. on the bowling ball
grigory [225]
It would exert the same back right?
3 0
3 years ago
It takes you 5 min to walk with an average velocity of .75 m/s to the north from the parking lot to the entrance of the amusemen
skad [1K]
A displacement is a vector quantity that takes into account the shortest distance from the starting point to the endpoint. 

The given above gave a time interval in minutes which needs to be converted to seconds. Given that each minute is 60 seconds, 5 minutes equal 300 seconds. To determine the distance, multiply time with speed. The product is 225 m. 

Thus, the displacement is 225 m. 
3 0
3 years ago
Which one of the following temperatures is equal to 5°C?
natali 33 [55]

Answer : The correct option is, (D) 278 K

Explanation :

We are given temperature 5^oC.

Now the conversion factor used for the temperature is,

K=^oC+273

where, K is kelvin and ^oC is Celsius.

Now put the value of temperature, we get

K=5^oC+273=278K

Therefore, the temperature 278 K is equal to the 5^oC


7 0
3 years ago
Find the electric energy density between the plates of a 225-μF parallel-plate capacitor. The potential difference between the p
PSYCHO15rus [73]

Answer:

Energy density will be 14.73 J/m^3

Explanation:

We have given capacitance C=225\mu F=225\times 10^{-6}F

Potential difference between the plates = 365 V

Plate separation d = 0.200 mm 0.2\times 10^{-3}m

We know that there is relation between electric field and potential

E=\frac{V}{d}, here E is electric field, V is potential and d is separation between the plates

So E=\frac{V}{d}=\frac{365}{0.2\times 10^{-3}}=1825000N/C

Energy density is given by E=\frac{1}{2}\varepsilon _0E^2=\frac{1}{2}\times 8.85\times 10^{-12}\times (1.825\times 10^6)^2=14.73J/m^3

5 0
3 years ago
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