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Anuta_ua [19.1K]
3 years ago
12

Classify the statement below as either Speed or Velocity?

Physics
1 answer:
Yuki888 [10]3 years ago
4 0

Answer:

Hello There!

It is Speed.

\Large\bold\red{Reason}

Because in the question it is said that at which speed car is travelling.

Speed is a scalar quantity.

If it is velocity then first know this that it is a vector quantity.

It must include both magnitude and direction.

If it is velocity then it would be 40 mph east or west or north or south.

<h2>I hope it is helpful to you...</h2><h3>Cheers!_____________</h3>
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Figure a shows a copper-colored cylinder of mass m and temperature change delta T. The heat Q, shown as a wavy rightward horizontal arrow, is transferred to the cylinder from the left. To the right of this image is a similar image, except that the heat transferred Q prime is twice the heat Q. The temperature change of this second cylinder, which is also labeled m, is two delta T. This cylinder is surrounded by small black wavy lines radiating outward. Figure b shows the same two cylinders as in Figure a. The left cylinder is labeled m and delta T and has a wavy heat arrow pointing at it from the left that is labeled Q. The right cylinder is labeled two m and delta T and has a wavy heat arrow pointing to it from the left labeled Q prime equals two Q. Figure c shows the same copper cylinder of mass m and with temperature change delta T, with heat Q being transferred to it. To the right of this cylinder, Q prime equals ten point eight times Q is being transferred to another cylinder filled with water whose mass and change in temperature are the same as that of the copper cylinder.

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3 years ago
How far does a car go in 30 seconds at a speed of 29 m/s? (The equation for<br> distance is d = st.)
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8 0
2 years ago
What must be the diameter of a cylindrical 120-m long metal wire if its resistance is to be 6.0 ω? the resistivity of this metal
Free_Kalibri [48]

The resistance of the cylindrical wire is R=\frac{\rho l}{A}.

Here R is the resistance, l is the length of the wire and A is the area of cross section. Since the wire is cylindrical A=\frac{\pi d^2}{4}. Rearranging the above equation,

A=\frac{\rho l}{R}\\  \frac{\pi d^2}{4}=\frac{\rho l}{R}\\  d=\sqrt{\frac{4\rho l}{\pi R}}

Here l=120, R=6, \rho=1.68(10^{-8}).

Substituting numerical values,

d=\sqrt{\frac{4(1.68)(10^{-8}) (120)}{\pi (6)}}\\ d=0.0006541

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4 years ago
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Answer:

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                            <em>     W  = F. S cos Θ</em>

<em>When cos Θ = 0° ; cos 0 = 1</em>

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3 years ago
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