119.7kPa
Explanation:
Given parameters:
Pressure of gas in balloon = 111kPa
Temperature of gas = 22°C
Final temperature = 45°C
Unknown:
Final pressure = ?
Solution:
Since the gases in the balloon have the same number of moles. We can apply a derivative of the combined gas law to solve this problem.
At constant volume the pressure of a given mass of gas varies directly with the absolute temperature.
P1 is the initial pressure
P2 is the final pressure
T1 is the initial temperature
T2 is the final temperature
convert from celcius to kelvin:
tK = 273 + tC
T1 = 273 + 22 = 295K
T2 = 273 + 45 = 318K
P2 = 119.7kPa
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Answer:
As it moves farther and farther away from Q, it's speed will keep increasing.
Explanation:
This is so because the point charges are both positive charges and positive charges repel.
As the charges repel, they do so at an increasing speed.
Answer: It has a range of visible and invisible forms of radiation.
Explanation:
Electromagnetic wave is defined as the wave which is associated with both electrical and magnetic component associated with them. They can travel in vacuum as well and travel with the speed of light i.e 
The electromagnetic radiations consist of radio waves, microwaves, infrared ,Visible , ultraviolet, X rays and gamma rays arranged in order of increasing frequency and decreasing wavelengths.
Only visible light is visible to naked eyes.
The relationship between wavelength and frequency of the wave follows the equation:
where,
= frequency of the wave
c = speed of light
= wavelength of the wave
From the above relation, it is visible that wavelength and frequency follow inverse relation. For increase in wavelength, the value of frequency decreases and vice-versa.
Answer: 655.7 nm
Explanation:
Given
The slits are separated by 
Distance between slits and screen is 
Adjacent bright fringes are 
apart
Also, the distance between bright fringes is given by
![\Rightarrow \beta =\dfrac{\lambda D}{d}\quad [\lambda=\text{Wavelength of light}]\\\\\text{Insert the values}\\\\\Rightarrow 2.88\times 10^{-3}=\dfrac{\lambda \cdot 2.24}{0.510\times 10^{-3}}\\\\\Rightarrow \lambda =\dfrac{2.88\times 10^{-3}\times 0.510\times 10^{-3}}{2.24}\\\\\Rightarrow \lambda =0.6557\times 10^{-6}\ m\\\Rightarrow \lambda =655.7\ nm](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cbeta%20%3D%5Cdfrac%7B%5Clambda%20D%7D%7Bd%7D%5Cquad%20%5B%5Clambda%3D%5Ctext%7BWavelength%20of%20light%7D%5D%5C%5C%5C%5C%5Ctext%7BInsert%20the%20values%7D%5C%5C%5C%5C%5CRightarrow%202.88%5Ctimes%2010%5E%7B-3%7D%3D%5Cdfrac%7B%5Clambda%20%5Ccdot%202.24%7D%7B0.510%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5C%5C%5CRightarrow%20%5Clambda%20%3D%5Cdfrac%7B2.88%5Ctimes%2010%5E%7B-3%7D%5Ctimes%200.510%5Ctimes%2010%5E%7B-3%7D%7D%7B2.24%7D%5C%5C%5C%5C%5CRightarrow%20%5Clambda%20%3D0.6557%5Ctimes%2010%5E%7B-6%7D%5C%20m%5C%5C%5CRightarrow%20%5Clambda%20%3D655.7%5C%20nm)
