an object has a length of 5.0 cm, aheight of 3.0 cm and a width of 15.0 cm. it has a mass of 24 grams. what is its density?

CCDs are _____ format detectors, which detect photons with _____ efficiency. analog, high analog, low digital, high digital, low

mars1129 [50]

High digital and high are the answers.

hope this helps

7 0

3 years ago

What type of conducting medium has the highest conductivity?

andreyandreev [35.5K]

I can't really answer this question without giving me any limits to the possibilities of the answers. However, I found a similar problem with a given set of choices. I think the answer is plasma. The medium that has the highest conductivity must be electric or ionized in nature. Since plasma is a very hot ionized gas, then it would be the most conductive out of all the choices.

3 0

3 years ago

What is the distance from the moon to the point between Earth and the Moon where the gravitational pulls of Earth and Moon are e

Ugo [173]

Answer:

the point between Earth and the Moon where the gravitational pulls of Earth and Moon are equal is <em>E)3.45 × 10⁸ m</em>

Explanation:

The force that the Earth exerts on a mass m is

F_e = (G M_e m) / R_e²

where

G is the universal gravitational constant
M_e is the mass of Earth
R_e is the radius of Earth

The force that the Moon exerts on a mass m is

F_m = (G M_m m) / R_m²

where

G is the universal gravitational constant
M_m is the mass of the Moon
R_m is the radius of the Moon

Therefore, the point where the gravitational pulls of Earth and Moon are equal is:

F_e = F_m

R_e + R_m = R = 3.84×10⁸ m

Thus,

(G M_e m) / R_e² = (G M_m m) / R_m²

M_e / R_e² = M_m / (R - R_e²)

(R - R_e²) / R_e² = M_m / M_e

(R - R_e) / R_e = (M_m / M_e)^1/2

R_e(R/R_e -1) / R_e = (M_m / M_e)^1/2

R/ R_e = (M_m / M_e)^1/2 + 1

R_e = R / [(M_m / M_e)^1/2 + 1]

R_e = (3.84×10⁸ m) / [(7.35 x 10²² kg / 5.97 x 10²⁴ kg )^1/2 + 1]

R_e = 3.45 × 10⁸ m

Therefore, the point between Earth and the Moon where the gravitational pulls of Earth and Moon are equal is <em>3.45 × 10⁸ m.</em>

4 0

3 years ago

1. You apply a force of 67.0 N to a mass of 1.43 kg. What is the acceleration of the object?

telo118 [61]

46.58m/s²

26.43kg

Explanation:

Given parameters:

Force = 67N force = 185N

Mass = 1.43kg acceleration = 7m/s²

Unknown:

Acceleration = ?

mass of the object = ?

Solution:

According to newton's second law of motion "the net force on a body is a product of its mass and acceleration".

Force = mass x acceleration;

For the first problem;

the unknown is the acceleration;

Acceleration = $\frac{force }{mass}$ = $\frac{67}{1.43}$ = 46.58m/s²

Using the same law, to find the mass of the second object, we make it the subject of the formula;

mass = $\frac{force }{acceleration}$

mass = $\frac{185}{7}$ = 26.43kg

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

4 0

3 years ago

An elevator is moving upwards at a constant velocity of 5 m/s. what is the net acceleration the elevator experiences

KatRina [158]

Sinc the elevator is moving at constant velocity, it experience no net force and thus no net acceleration is experienced by the elevator. a=0ms^-2

6 0

4 years ago