of
is present in 15 g of
.
Further explanation:
Amount of substance is measured in terms of mole. The mass of substance with same number of fundamental units as atoms in 12 g of carbon 12 is 1 mole.
In step 1, we have to calculate the molar mass of
. The molar mass of
can be calculated by using equation (1).
Step 1: The molar mass of
is calculated as follows:
![{\text{Molar mass of}}{\mathbf{ }}{{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} = \left[ \begin{gathered}{\text{2}}\left( {{\text{Atomic mass of K}}} \right)+\hfill\\{\text{1}}\left({{\text{Atomic mass of S}}} \right)+\hfill\\{\text{4}}\left({{\text{Atomic mass of O}}}\right)\hfill\\\end{gathered}\right]](https://tex.z-dn.net/?f=%7B%5Ctext%7BMolar%20mass%20of%7D%7D%7B%5Cmathbf%7B%20%7D%7D%7B%7B%5Ctext%7BK%7D%7D_%7B%5Ctext%7B2%7D%7D%7D%7B%5Ctext%7BS%7D%7D%7B%7B%5Ctext%7BO%7D%7D_%7B%5Ctext%7B4%7D%7D%7D%20%3D%20%5Cleft%5B%20%5Cbegin%7Bgathered%7D%7B%5Ctext%7B2%7D%7D%5Cleft%28%20%7B%7B%5Ctext%7BAtomic%20mass%20of%20K%7D%7D%7D%20%5Cright%29%2B%5Chfill%5C%5C%7B%5Ctext%7B1%7D%7D%5Cleft%28%7B%7B%5Ctext%7BAtomic%20mass%20of%20S%7D%7D%7D%20%5Cright%29%2B%5Chfill%5C%5C%7B%5Ctext%7B4%7D%7D%5Cleft%28%7B%7B%5Ctext%7BAtomic%20mass%20of%20O%7D%7D%7D%5Cright%29%5Chfill%5C%5C%5Cend%7Bgathered%7D%5Cright%5D)
…… (1)
The atomic mass of K is 39.09 g.
The atomic mass of S is 32.06 g.
The atomic mass of O is 16 g.
Substitute these values in equation (1).
![\begin{aligned}{\text{Molar mass of}}{\mathbf{ }}{{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}&=\left[{{\text{2}}\left({{\text{39}}{\text{.09 g}}}\right)+{\text{1}}\left({{\text{32}}{\text{.06 g}}}\right)+{\text{4}}\left({{\text{16 g}}}\right)}\right]\\&=\left[{{\text{78}}{\text{.18 g}}+{\text{32}}{\text{.06 g}}+{\text{64 g}}}\right]\\&=174.24\;{\text{g/mol}}\\\end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%7B%5Ctext%7BMolar%20mass%20of%7D%7D%7B%5Cmathbf%7B%20%7D%7D%7B%7B%5Ctext%7BK%7D%7D_%7B%5Ctext%7B2%7D%7D%7D%7B%5Ctext%7BS%7D%7D%7B%7B%5Ctext%7BO%7D%7D_%7B%5Ctext%7B4%7D%7D%7D%26%3D%5Cleft%5B%7B%7B%5Ctext%7B2%7D%7D%5Cleft%28%7B%7B%5Ctext%7B39%7D%7D%7B%5Ctext%7B.09%20g%7D%7D%7D%5Cright%29%2B%7B%5Ctext%7B1%7D%7D%5Cleft%28%7B%7B%5Ctext%7B32%7D%7D%7B%5Ctext%7B.06%20g%7D%7D%7D%5Cright%29%2B%7B%5Ctext%7B4%7D%7D%5Cleft%28%7B%7B%5Ctext%7B16%20g%7D%7D%7D%5Cright%29%7D%5Cright%5D%5C%5C%26%3D%5Cleft%5B%7B%7B%5Ctext%7B78%7D%7D%7B%5Ctext%7B.18%20g%7D%7D%2B%7B%5Ctext%7B32%7D%7D%7B%5Ctext%7B.06%20g%7D%7D%2B%7B%5Ctext%7B64%20g%7D%7D%7D%5Cright%5D%5C%5C%26%3D174.24%5C%3B%7B%5Ctext%7Bg%2Fmol%7D%7D%5C%5C%5Cend%7Bgathered%7D)
In step 2, the molar mass calculated in step 1 is used to calculate the number of moles of
. The number of moles of
is calculated by using equation (2).
Step 2: The formula to calculate the moles of
is as follows:

…… (2)
The given mass of
is 15 g.
The molar mass of
is 174.24 g/mol.
Substitute these values in equation (2).

Learn more:
1. Calculate the moles of ions in the solution: <u>brainly.com/question/5950133
</u>
2. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: <u>brainly.com/question/3064603
</u>
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Mole concept
Keywords: molar mass, mole, K2SO4, 0.0860 mol, given mass, atomic mass, K, S, O, 16 g, 32.06 g, 39.09 g, 15 g, 174.24 g/mol.