Answer:
-209 kJ
Explanation:
I did the math. You're welcome ;)
Besides producing hydrogen ions in water, all Arrhenius acids have a few things in common. They have pH values anywhere from 0 up to 7, they taste and smell sour and they will turn pH paper pink, red, or orange.
<h3>What Arrhenius acids?</h3>
A substance that raises the concentration of H+ ions in an aqueous solution is known as an Arrhenius acid. Traditional Arrhenius acids are highly polarized covalent substances that dissociate in water to form an anion (A-) and the cation H+.
Aqueous Arrhenius acids have distinguishing characteristics that serve as a useful definition of an acid. Acids can turn blue litmus red, produce aqueous solutions with a sour taste, and react with bases and some metals (like calcium) to generate salts. The Latin word acidus/acre, which means "sour," is where the word acid originates.
Although the precise definition solely refers to the solute, the term "acid" is sometimes used to refer to an aqueous solution of an acid that has a pH lower than 8.
To learn more about Arrhenius acids from the given link:
brainly.com/question/22095536
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Answer:
The percentage deviation is 
%
Explanation:
From the question we are told that
The concentration is of the solution is 
The true absorbance A = 0.7526
The percentage of transmittance due to stray light 
% 
Generally Absorbance is mathematically represented as
Where T is the percentage of true transmittance
Substituting value
%
The Apparent absorbance is mathematically represented
Substituting values
= 0.7385
The percentage by which apparent absorbance deviates from known absorbance is mathematically evaluated as
%
Since Absorbance varies directly with concentration the percentage deviation of the apparent concentration from know concentration is
%
Answer:
49.5J/°C
Explanation:
The hot water lost some energy that is gained for cold water and the calorimeter.
The equation is:
Q(Hot water) = Q(Cold water) + Q(Calorimeter)
<em>Where:</em>
Q(Hot water) = S*m*ΔT = 4.184J/g°C*54.56g*(80.4°C-59.4°C) = 4794J
Q(Cold water) = S*m*ΔT = 4.184J/g°C*47.24g*(59.4°C-40°C) = 3834J
That means the heat gained by the calorimeter is
Q(Calorimeter) = 4794J - 3834J = 960J
The calorimeter constant is the heat gained per °C. The change in temperature of the calorimeter is:
59.4°C-40°C = 19.4°C
And calorimeter constant is:
960J/19.4°C =
<h3>49.5J/°C</h3>
<em />
It is a weighted average of the atomic masses of the naturally occurring isotopes of the element.
