ΔG° for the reaction is 5.47kJ mol⁻¹.
The energy that a substance has available for utilization in a chemical reaction or transformation is known as the Gibbs free energy. Things frequently change into other things that have less Gibbs free energy. The Gibbs free energy change indicates whether a chemical reaction will take place spontaneously or not.
By using the formula;
ΔG° = −RTlnKp
Where,
R = 8.3Jk⁻¹mol⁻¹
T = Temperature = 427 + 273 = 700 K
Kp = 8×10⁻⁵(given)
Substituting the value, we get,
ΔG° = −8.3 × 700 × ln(23×10⁻⁵)
ΔG° = −8.3 × 700 × (ln(2³)+ln 10⁻⁵)
= - 8.3 × 700 × (ln(2³)+ln 10⁻⁵)
= − 8.3 × 700 × (2.07−11.5)
=5.47×10⁴Jmol¹
=5.47kJ mol⁻¹
Therefore, ΔG° for the reaction is 5.47kJ mol⁻¹.
Learn more about Gibbs free energy here:
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The coefficient for aluminium is 4.
Explanation:
We have the following chemical reaction:
Al + O₂ → Al₂O₃
In order to balance the chemical equation the number of the atoms entering the reaction should be equal to the number of atoms leaving the reaction.
2 Al + 3/2 O₂ → Al₂O₃
However we need integer numbers so we multiply everything with 2.
4 Al + 3 O₂ → 2 Al₂O₃
The coefficient for aluminium is 4.
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about balancing chemical equations
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Answer:
Reactants have more energy than products
Explanation:
Generally, in an exothermic reaction heat is released. In other words, energy is released. So you start with reactants which have a set amount of stored chemical energy, and you lose some in the reaction. Since energy is 'leaving', the stored chemical energy in the products is less than what we started with in the reactants. When given a graph, you can tell this is true because going from left to right, the line representing the stored chemical energy will start at a higher level than where it ends.
Answer:
The new molarity is 0,1359M.
Explanation:
A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).
We use the formula for dilutions:
C1 x V1 = C2 x V2
0,60 M x 0,639 L= C2 x 2,822 L
C2=(0,60 M x 0,639 L)/ 2, 822 L
<em>C2=0,1359 M</em>
