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2 years ago

I need help wit this

Chemistry

2 answers:

Nataly_w [17]2 years ago

4 0

$\\ \sf\longmapsto2 Ca+O_2\longrightarrow 2CaO$

Balanced

$\\ \sf\longmapsto N_2+3H_2\longrightarrow 2NH_3$

Balanced

$\\ \sf\longmapsto 2Cu_2O+C\longrightarrow 4Cu+CO_2$

Balanced

$\\ \sf\longmapsto H_2O_2\longrightarrow H_2O+O_2$

Already balanced

Olenka [21]2 years ago

3 0

Answer: What are you german

Explanation:

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What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?

Ymorist [56]

Answer:

$\% diss = 50\%$

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

$HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}$

Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

$Ka=\frac{x^2}{[HA]_0-x} =10^{-4.74}=1.82x10^{-5}$

Thus, it is possible to find x given the pH as shown below:

$x=10^{-pH}=10^{-4.74}=1.82x10^{-5}M$

So that we can calculate the initial concentration of the acid:

$\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\$

$[HA]_0=3.64x10^{-5}M$

Therefore, the percent dissociation turns out to be:

$\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%$

Best regards!

6 0

2 years ago

Calculate the volume of a 3.50 M solution of H2SO4 made from 49 g of H2SO4

maxonik [38]

Answer:

0.143L

Explanation:

Molar mass of H2SO4 = 98g/Mol

No of mole = mass/molar mass

No of mole= 49/98 = 0.5 mol

No of mol = concentration × volume

Volume = n/C = 0.5/3.5 = 0.143L

3 0

3 years ago

When solving a problem it is important to identify your given and needed units, but it is also important to understand the relat

Angelina_Jolie [31]

Answer:

The question has some details missing. here are the details ; Given the following ;

1. 43.2 g of tablet with 20 cm3 of space

2. 5 cm3 of tablets weighs 10.8 g

3. 5 g of balsa wood with density 0.16 g/cm3

4. 150 g of iron. With density 79g/cm 3

5. 32 cm3 sample of gold with density 19.3 g/cm3

6. 18 ml of cooking oil with density 0.92 g/ml

Explanation:

Appropriate for calculating mass

32 cm3 sample of gold with density 19.3 g/cm3

18 ml of cooking oil with density 0.92 g/ml

Appropriate for calculating volume

5 g of balsa wood with density 0.16 g/cm3

150 g of iron. With density 79g/cm 3

Appropriate for calculating density

43.2 g of tablet with 20 cm3 of space

5 cm3 of tablets weighs 10.8 g

3 0

3 years ago

A decrease in the magnitude of velocity is called

IceJOKER [234]

The answer is deceleration. Acceleration is the general term to refer to the change in velocity. Acceleration = change in velocity / change in time. When you want to highlight the fact that the change in velocity is a decrease in the magnitude, you can use the term deceleration, which means that the acceleration is negative.

3 0

3 years ago

How many values of these of these trials can be considered accurate?

Gnoma [55]

Answer:

go to google

Explanation:it all ways work

6 0

3 years ago