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seraphim [82]
3 years ago
15

Chemical decontamination can be accomplished with liquids such as chlorox, Lysol, amphyl or a gas such as ethylene oxide.

Chemistry
1 answer:
TEA [102]3 years ago
4 0

Answer:

True

Explanation:

Chemical decontamination -

It is the process of elimination or reduction of contaminants like hazardous materials and microorganisms , where chemicals and radioactive substances are used , is referred to as chemical decontamination.

The process helps to reduce the micro organisms and various other contaminants .

The liquids used for the this process are Amphyl , Lysol , Chlorox etx.

Hence, from the given statement of the question is true.

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D) The electrons move around the nucleus in an electron cloud

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Which of the following statements about gamma rays are TRUE? I. Gamma rays have low energy II. Gamma rays are a form of light. I
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Calculate the enthalpy of the reaction
harkovskaia [24]

Answer : The enthalpy of the reaction is, -2552 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given enthalpy of reaction is,

4B(s)+3O_2(g)\rightarrow 2B_2O_3(s)    \Delta H=?

The intermediate balanced chemical reactions are:

(1) B_2O_3(s)+3H_2O(g)\rightarrow 3O_2(g)+B_2H_6(g)     \Delta H_A=+2035kJ

(2) 2B(s)+3H_2(g)\rightarrow B_2H_6(g)    \Delta H_B=+36kJ

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_C=-285kJ

(4) H_2O(l)\rightarrow H_2O(g)    \Delta H_D=+44kJ

Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :

(when we are reversing the reaction then the sign of the enthalpy change will be change.)

The expression for enthalpy of the reaction will be,

\Delta H=-2\times \Delta H_A+2\times \Delta H_B-6\times \Delta H_C-6\times \Delta H_D

\Delta H=-2(+2035kJ)+2(+36kJ)-6(-285kJ)-6(+44)

\Delta H=-2552kJ

Therefore, the enthalpy of the reaction is, -2552 kJ/mole

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3 years ago
What is the lewis dot structure of NaBr
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