Answer:
True.
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
the photosynthesis the of 14 showed me by diameting the equation of the perpendicularcity of the dude with lactose intolerantcey
Mary's house is approximately 49.73 miles from her grandmother's house.
The distances the three drove were;
Mary drove for 49.73 miles, Theo drove 50 miles and Nancy drove 53.299 miles.
Explanation:
- The given triangle has a 13 mile long adjacent side, a 48 mile long opposite side and the distance of Mary's route is the hypotenuse. As we have two sides of the triangle, we can solve for the length of the other side by using Pythagoras' theorem.
- Assume the hypotenuse of the triangle measures x miles. According to Pythagoras theorem, x = √(13² + 48²) , x = √169 + 2,304 x = √2,473 = 49.729. Rounding this off, we get Mary's route was 49.73 miles long.
- Nancy drove √2,840 miles = 53.2916 miles.
- So Mary drove the shortest distance of 49.73 miles, second shortest was Theo who drove for 50 miles and the longest was Nancy who drove for 53.299 miles.
Answer:
1/3
Step-by-step explanation:
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work
EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same
For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y
For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4
Therefore, for the two expressions to be conjugates, we must satisfy the two conditions.
Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the
x²y = -4 ... (I)
Condition 2: Real parts are the same
x² + y = -3 ... (II)
We have a system of equations since both conditions must be satisfied
x²y = -4 ... (I)
x² + y = -3 ... (II)
We can rearrange equation (II) so that we have
y = -3 - x² ... (II)
Substituting into equation (I)
x²y = -4 ... (I)
x²(-3 - x²) = -4
-3x² - x⁴ = -4
x⁴ + 3x² - 4 = 0
(x² + 4)(x² - 1) = 0
(x² + 4)(x-1)(x+1) = 0
Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.
Solve for y:
y = -3 - x² ... (II)
y = -3 - (±1)²
y = -3 - 1
y = -4
So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:
-3 + ix²y
= -3 + i(±1)²(-4)
= -3 - 4i
x² + y + 4i
= (±1)² - 4 + 4i
= 1 - 4 + 4i
= -3 + 4i
They result in conjugates
