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3 years ago

WILL UPVOTE EVERY ANSWER! MULTIPLE CHOICE!

Physics

1 answer:

Ad libitum [116K]3 years ago

8 0

D = m /v
d = 30 / 0.5 Kg/m³
d = 60 Kg / m³

In short, Your Answer would be Option A

Hope this helps!

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A 1.00 kg object is attached to a horizontal spring. the spring is initially stretched by 0.500 m, and the object is released fr

valina [46]

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$T=2 t = 2 \cdot 0.100 s = 0.200 s$
Which means that the frequency is
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and the angular frequency is
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In a spring-mass system, the maximum velocity of the object is given by
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$v_{max} = A \omega = (0.500 m)(31.4 rad/s)= 15.7 m/s$

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Vladimir [108]

Answer:

we assume that it starts with a velocity of 10m/s. At 2m height above ground level, its velocity decreases at 3m above ground level

for its way down the velocity at 3m on its way down is more than its velocity at 2m on its way down.

Explanation:

A student throws a small rock straight upwards. The rock rises to its highest point and then falls back down. How does the speed of the rock at 2m on the way down compare with its speed at 2m on the way up?

It decreases in speed on its way down and increases in speed on its way down.

it decreases in speed on its way up because the the vertical motion is against the earths gravitational pull on an object to the earth's center

.It increases in speed on his way down because its under the influence of gravity

from newton's equation of motion we can check by

using V^2=u^2+2as

we assume that it starts with a velocity of 10m/s. At 2m height above ground level, its velocity decreases at 3m above ground level

for its way down the velocity at 3m on its way down is more than its velocity at 2m on its way down.

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