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2 years ago

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How many carbon atoms placed end to end would equal the width of a human hair

1 answer:

xz_007 [3.2K]2 years ago

3 0

The carbon atoms placed end to end would equal the width of a human hair are 1 million.

<h3>What is carbon?</h3>

The carbon is an element in the periodic table. It has atomic number 6 and the atomic mass 12 units.

Molecules anyway can shift in size from 0.1-0.5nm (nanometres) across so it would take a component of around 100,000 particles in width so that us might be able to see it with the unaided eye. Assuming that there's around 100,000 molecules in the width of one piece of hair, envision the number of there are in objects around you.

Learn more about carbon.

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a body of mass 0.2kg is whirled round a horizontal circle by a string inclined at 30 degrees to the vertical calculate <br /&

Katen [24]

Answer:

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Explanation:

We use Newton's second law

Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string

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cos 30 = $\frac{T_y}{T}$

Tₓ = T sin 30

T_y = T cos 30

Y axis

T_y -W = 0

T cos 30 = mg (1)

X axis

Tₓ = m a

they relate it is centripetal

a = v² / r

we substitute

T sin 30 = m $\frac{v^2}{r}$ (2)

a) we substitute in 1

T = $\frac{mg }{cos 30}$

T = $\frac{ 0.2 \ 9.8}{cos \ 30}$

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b) from equation 2

v² = $\frac{T \ sin 30 \ r}{m}$

If we know the length of the string

sin 30 = r / L

r = L sin 30

we substitute

v² = $\frac{ T \ sin 30 \ L \ sin 30}{m}$

v² = $\frac{TL \ sin^2 30}{m}$

For the problem let us take L = 1 m

let's calculate

v = $\sqrt{ \frac{2.26 \ 1 \ sin^230}{0.2} }$

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2 years ago

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Art [367]

Answer:

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Explanation:

$L_1$ = Length of wire = 65 m

$I_1$ = Initial current = 1.8 A

$I_2$ = Final current = 2.9 A

We know

$R\propto \dfrac{1}{I}$

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