Answer:
By exact formula
5076.59N/C
And by approximation formula
5218.93N/C
Explanation:
We are given that
Length of rod,L=2.6 m
Charge,q=98nC=
a=13 cm=0.13 m
1 m=100 cm
By exact formula
The magnitude of the electric field due to the rod at a location 13 cm from the midpoint of the rod=
Where k=
Using the formula
The magnitude of the electric field due to the rod at a location 13 cm from the midpoint of the rod=
In approximation formula
a<<L
Therefore,the magnitude of the electric field due to the rod at a location 13 cm from the midpoint of the rod=
The magnitude of the electric field due to the rod at a location 13 cm from the midpoint of the rod=
Because they have no opposing fields to cancel their effects, these electrons have an orbital magnetic. Magnetic moments<span> come from the moments of all of its </span>atoms<span>.</span>
Answer:
Work, W = F * d, and
Work = change in kinetic energy, so W=deltaKE.
Hence,
deltaKE=F * d
(1/2)*m*v^2 =F * d
d=[(1/2)*m*v^2]/F
d=[(1/2)*0.6*20^2]/5
d=24 m.
Explanation:
Work = change in kinetic energy, so W=deltaKE.
<>"Topographic maps conventionally show topography, or land contours, by means of contour lines. Contour lines are curves that connect contiguous points of the same altitude (isohypse). In other words, every point on the marked line of 100 m elevation is 100 m above mean sea level."<> I hope this helps.
Answer:
The total kinetic energy of the system before the collision is 57 Joules.
Explanation:
Given that,
Mass of first block,
Speed of first block,
Mass of second block,
Speed of first block,
We need to find the total kinetic energy of the system before the collision. It is equal to the kinetic energies of both the blocks. It is given by :
So, the total kinetic energy of the system before the collision is 57 Joules.