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Naya [18.7K]
3 years ago
7

calculate your power in watts if you do 500 N*m of work picking up a dumbbell,and takes 5 s to perform that task?​

Physics
1 answer:
Slav-nsk [51]3 years ago
6 0

Answer:

100watts

Explanation:

Given parameters:

Workdone  = 500Nm

Time taken = 5s

Unknown:

Power in watts = ?

Solution:

Power is the rate at which work is done;

   Power  =\frac{workdone }{time}

Input the parameters and solve;

   Power = \frac{500}{5}  = 100watts

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A paper-filled capacitor is charged to a potential difference of V0=2.5 V. The dielectric constant of paper is k=3.7 . The capac
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Answer:

k =  6.72

Explanation:

K of paper = 3.7

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Given that charge Q on the capacitor is constant because cell is disconnected from the circuit. So

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Capacity becomes C / 3.7 in air .

capacity becomes C/3.7 when paper is replaced by air .

V₁ = Q / (C/3.7)

= 3.7 Q/C

3.7 x 2.5

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In the second case ,

capacitance  due to new unknown dielectric k

= C/3.7 x k

= kC / 3.7 ( Capacitance in air is C/3.7 )

V ( new ) = Q / ( kC/3.7 )

= 3.7 Q/kC

.55 x 2.5 = 3.7 x( 2.5 / k )

k = 3.7 / .55

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2 years ago
A ball with a weight of 2 N is attached to the end of a cord of length 2m . The ball is whirl in a vertical circle counterclockw
ZanzabumX [31]

Answer:

we agree with

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Explanation:

Weight of the ball is given as

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so we have

m = \frac{W}{g}

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now tension force at the top is given as

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2) Weight of the ball

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F_{net} = T + W

F_{net} = 7 + 2 = 9 N

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Edgar: The net force on the ball at the top position is 9 N. Both the tension and the weight are acting downward so you have to add them.

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Two charged particles separated by a distance of = 3 and experienced electrostatic forces of = 60 . What would be this force if
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Answer: 539.4 N

Explanation:

Let's begin by explaining that Coulomb's Law establishes the following:  

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"

What is written above is expressed mathematically as follows:

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