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NISA [10]
3 years ago
9

Soils refers to natural material from the earth, but not artificial material (like AstroTurf or asphalt). True False

Physics
2 answers:
Lelu [443]3 years ago
6 0

Answer:

It is true that Soil refers to natural material from the earth, but not artificial material (like AstroTurf or asphalt).  

Artificial materials are the materials that are made by human like AstroTurf or asphalt  while Soil is one of the natural materials giving to us by God. Soil is a material composed of five ingredients which are minerals, soil organic matter, living organisms, gas, and water.

 

adelina 88 [10]3 years ago
4 0

Answer:

It's False

Explanation:

i just took the test

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Ayuda por favor (archivo adjunto) con un ejercicio de expresión sobre periodo de oscilación de esta figura:
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[04.05] An atom has an atomic number of 12 and a mass number of 25. How many neutrons does the atom have?​
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3 years ago
A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of
Papessa [141]

The magnitude (in N) of the force she must exert on the wrench is 150.1 N.

<h3>Force exerted by the wrench</h3>

The force exerted by the wrench is calculated using torque formula as follows;

torque, τ = F x r x sinθ

where;

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  • r is the perpendicular distance if force applied

F =  τ /(r sinθ)

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Thus, the magnitude (in N) of the force she must exert on the wrench is 150.1 N.

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5 0
2 years ago
A flywheel in a motor is spinning at 590 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75
Gnom [1K]

Answer:

Explanation:

Hello,

Let's get the data for this question before proceeding to solve the problems.

Mass of flywheel = 40kg

Speed of flywheel = 590rpm

Diameter = 75cm , radius = diameter/ 2 = 75 / 2 = 37.5cm.

Time = 30s = 0.5 min

During the power off, the flywheel made 230 complete revolutions.

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + ω₂) / 2] × 0.5

But ∇θ = 230 revolutions

∇θ/t = (530 + ω₂) / 2

230 / 0.5 = (530 + ω₂) / 2

Solve for ω₂

460 = 295 + 0.5ω₂

ω₂ = 330rpm

a)

ω₂ = ω₁ + αt

but α = ?

α = (ω₂ - ω₁) / t

α = (330 - 590) / 0.5

α = -260 / 0.5

α = -520rev/min

b)

ω₂ = ω₁ + αt

0 = 590 +(-520)t

520t = 590

solve for t

t = 590 / 520

t = 1.13min

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X seconds = 1.13min

x = (60 × 1.13) / 1

x = 68seconds

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + 0) / 2] × 1.13

∇θ = 333.35 rev/min

8 0
3 years ago
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