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NeTakaya
3 years ago
8

Why is the steering of a car wheel and axle​

Physics
2 answers:
Effectus [21]3 years ago
8 0

Answer:

because a smaller cylinder shaped wheel, called the axel ,connects the wheels on a car.

Sauron [17]3 years ago
5 0

Answer:

have a greater mechanical advantage

Explanation:

this enables the mechanism to output a large amount of force compared to the force put into it due to ratio of the wheel and the axle therefore providing enough force to steer the rather heavy wheels while saving the driver some muscle power

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Prof. Kopp is working on an experiment located in an abandoned mine near Duluth, MN. The experiment is located approximately 713
MA_775_DIABLO [31]

Answer:

The average speed of the elevator going down in the abandoned mine is 17.722mph.

Explanation:

If the elevator takes 90 seconds to descend a height of 713m, the average speed of the elevator is:

v_{av}=x_T/t_T=713m/90s=7.922m/s

And if 1m/s is 2.23694mph, the average speed is:

v_{av}=7.922m/s=17.722mph.

8 0
3 years ago
When a force is exerted on an object, does a large force always produce a larger change in the object's momentum than a smaller
baherus [9]
Yes .because the larger or more amount of pressuer will make moer of a compact . than a smaller one would
8 0
3 years ago
A plastic rod rubbed with a duster attracts bits of paper becauseof a what force
likoan [24]
Its because of the static electricity.As we rub, the positive and negative charges are acquired by the plastic rod and duster.
If we bring paper bits near them, the charges possessed by the paper bits get attracted towards the charges in plastic rod.

5 0
2 years ago
A diffusion couple, made by welding a thin onecentimeter square slab of pure metal A to a similar slab of pure metal B, was give
bezimeni [28]

Answer:

The value  is    H  =  18*10^{2} \  Atom / sec

Explanation:

From the question we are told that

  The atom fraction of metal A at point G is A  =  0.30 \ m

   The atom fraction of metal  A at a distance 5000nm from G is  A_2 = 0.35

   The number of atoms per m^3 is    N_h =  9 * 10^{28}

    The diffusion coefficient is  D =   2* 10^{-14 } m^2/s

Generally of the concentration of atoms of metal A at G is  

       N_A = A * N_h

=>    N_A =  0.3  * 9 * 10^{28}

=>     N_A =   2.7 * 10^{28} 2.7 atoms/m^3

Generally of the concentration of atoms of metal A at a distance 5000nm from G is  

       D =  0.35 *9 * 10^{28}

=>     D =  3.15 * 10^{28} \  atoms / m^3

The concentration gradient is mathematically represented as

   \frac{dN_A}{dx}  =  \frac{(3.15 - 2.7) * 10^{28} }{5000nm - 0 }

=> \frac{dN_A}{dx}  =  \frac{(3.15 - 2.7) * 10^{28} }{[5000 *10^{-9}] - 0 }  

=>   \frac{dN_A}{dx}  = 9 * 10^{20} / m^4  

Generally the flux of the atoms per unit  area according to Fick's Law  is mathematically represented as

       J =  -D* \frac{d N_A}{dx}

=>    J =  -2* 10^{-14 * 9 * 10^{20}

=>    J =  18*10^{6}\   atoms\ crossing\ /m^2 s

Generally if the cross-section area is a  =  1 cm^2 =  10^{-4} \  m^2

Generally the number of atom crossing the above area  per second is mathematically is  

      H  =  18*10^{6}    *  10^{-4}

=>    H  =  18*10^{2} \  Atom / sec

7 0
3 years ago
Somebody please help me!! Timed test
Olegator [25]

Answer: i dont know sorry

Explanation:

3 0
3 years ago
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