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lyudmila [28]
3 years ago
14

A person lowers a bucket into a well by turning the hand crank, as the drawing illustrates. The crank handle moves with a consta

nt tangential speed of 1.81 m/s on its circular path. The rope holding the bucket unwinds without slipping on the barrel of the crank. Find the linear speed with which the bucket moves down the well.
Physics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

0.453 m/s

Explanation:

Assuming the handle has diameter of 0.4 m while inner part diameter is 0.1 m then the circumference of outer part is \pi d_h where d is diameter and subscript h denote handle. By substituting 0.4 for the handle's diameter then cirxumference of outer part is \pi\times 0.4\approx 1.256 m

The rate of rotation will then be 1.81/1.256=1.441 rev/s

Similarly, circumference of inner part will be \pi d_i where subscript i represent inner. Substituting 0.1 for inner diameter then

\pi\times 0.1\approx 0.3142 m

The rate of rotation found for outer handle applies for inner hence speed will be 0.3142*1.441=0.453 m/s

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2 years ago
Lonnie pitches a baseball of mass 0.20 kg. The ball arrives at home plate with a speed of 40 m/s and is batted straight back to
abruzzese [7]

Answer:

B) 20N.s is the correct answer

Explanation:

The formula for the impulse is given as:

Impulse = change in momentum

Impulse = mass × change in speed

Impulse = m × ΔV

Given:

initial speed  = 40m/s

Final speed = -60 m/s (Since the the ball will now move in the opposite direction after hitting the bat, the speed is negative)

mass = 0.20 kg

Thus, we have

Impulse = 0.20 × (40m/s - (-60)m/s)

Impulse = 0.20 × 100 = 20 kg-m/s or 20 N.s

6 0
3 years ago
In 0.60 seconds, a projectile goes from 0 to 610 m/s. What is the acceleration of the projectile?
IceJOKER [234]

Answer: a=1016.66 m/s^{2}

Explanation:

Acceleration a is expressed in the following formula:

a=\frac{V_{f}-V_{o}}{t}

Where:

V_{f}=610 m/s is the final velocity of the projectile

V_{o}=0 m/s  is the initial velocity of the projectile

t=0.6 s is the time

Solving:

a=\frac{610 m/s-0 m/s}{0.6 s}

a=1016.66 m/s^{2} This is the acceleration of the projectile

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