Answer:
Tc = 168°C
Explanation:
Carnot engine:
∴ ε: efficiency = 60% = 0.60
∴ Th: hot-reservoir temperature = 420°C
∴ Tc: cold-reservoir temperature = ?
⇒ Tc = (1 - ε)×Th
⇒ Tc = ( 1 - 0.60 )×( 420 °C )
⇒ Tc = 168°C
Answer:
2.042 g
Explanation:
The reaction that takes place is:
- 2HCl + Mg(OH)₂ → Mg²⁺ + 2Cl⁻ + 2H₂O
First we <u>calculate how many HCl moles were added</u>, using <em>the given volume and concentration</em>:
- 30 mL ⇒ 30 / 1000 = 0.030 L
- 5.6 M * 0.030 L = 0.168 mol HCl
Then we<u> convert HCl moles into Mg²⁺ moles</u>, using the<em> stoichiometric coefficients</em>:
- 0.168 mol HCl *
= 0.084 mol Mg⁺²
Finally we <u>convert Mg moles into grams</u>, using its<em> molar mass</em>:
- 0.084 mol Mg⁺² * 24.305 g/mol = 2.042 g
I do believe the answer would be physical
<span>A sample of C3H8 has 3.20 × 10^24 H atoms.
We will use Avogadro's number for this problem. Avogadro's number states that there are 6.022x 10^23 atoms per mole of a substance. We will use dimensional analysis, notice how the units cancel in the computation below:
</span>3.20 × 10^24 atoms H * (1 mole H/6.022x 10^23 atoms H) * (3 moles C/8 moles H) * (6.022x 10^23 atoms C/1 mole C) = 1.2 x 10^24 atoms C
To get the total mass of the sample in grams, let us note that there are 3 moles of carbon and 8 moles of hydrogen per mole of C3H8, and using the molecular weights of C (12 g/mol) and H (1 g/mol), we get (12*3)+(1*8)= 44 g/mol as the molar mass.
3.20 × 10^24 atoms H * (1 mole H/6.022x 10^23 atoms H) * (1 mole C3H8/8 moles H) * (44 g C3H8 / 1 mole C3H8) = 29.23 g C3H8<span>
</span>
Answer: The mass in grams of sodium carbonate is 34.3 g
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,
n = moles of solute
= volume of solution in ml
moles of
= 
Now put all the given values in the formula of molarity, we get


Therefore, the mass in grams of sodium carbonate is 34.3 g