Answer:
The concentration of helium in the water is 2.405×10^-4 M
Explanation:
Concentration = Henry's law constant × partial pressure of helium
Henry's law constant = 3.7×10^-4 M/atm
Partial pressure of helium = 0.65 atm
Concentration = 3.7×10^-4 × 0.65 = 2.405×10^-4 M
Copper<span>(II) </span>oxide<span> or cupric </span>oxide<span> is the inorganic </span>compound<span> with the formula CuO. A black solid, it is one of the two stable </span>oxides<span> of </span>copper, the other being Cu2<span>O or cuprous </span>oxide<span>. As a mineral, it is known as tenorite and paramelaconite.</span>
Answer:
We need 12.26 grams H2SO4
Explanation:
Step 1: Data given
Volume of a H2SO4 solution = 500 mL = 0.500 L
Concentration of the H2SO4 solution = 0.250 M
Molar mass of H2SO4 = 98.08 g/mol
Step 2: Calculate moles H2SO4
Moles H2SO4 = concentration * volume
Moles H2SO4 = 0.250 M * 0.500 L
Moles H2SO4 = 0.125 moles
Step 3: Calculate mass of H2SO4
Mass of H2SO4 = moles * molar mass
Mass of H2SO4 = 0.125 moles * 98.08 g/mol
Mass of H2SO4 = 12.26 grams
We need 12.26 grams H2SO4
Answer:
1 mole of gas = 22.4L
2.5 moles of gas takes up = ( 22.4 L/ 1 mole ) x 2.5 mole
= 56 L
Explanation:
Please mark brainliest and have a great day!
It'll beginning to evaporate.
