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Juliette [100K]
3 years ago
7

7.8g of dioxide would be produced from how many moles of potassium chlorate

Chemistry
1 answer:
Ghella [55]3 years ago
6 0
2KClO₃ ⇒ 2KCl + 3O₂
2mol         :            3mol
245,1g      :           95,94g
x               :           7,8g

x = 7,8g*245,1g / 95,94g = 19,93g

1mol of KClO₃ --------- is --------- 122,55g
x mol               --------- is --------- 19,93g

x = 19,93g*1mol / 122,55g = 0,158mol
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Thanks for the help :) Question attached below:
Alekssandra [29.7K]

• Take a look at the steps below to see how to balance this equation. Let's start by writing the unbalanced equation given the information.

Unbalanced Equation : C₃H₈ (g) + O₂ (g) → CO₂ (g) + H₂O (g) ,

Start by Balancing the Carbons : C₃H₈ (g) + O₂ (g) → 3CO₂ (g) + H₂O (g)

Now let's balance the Hydrogen : C₃H₈ (g) + O₂ (g) → 3CO₂ (g) + 4H₂O (g)

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•  Similarly we can identify the liters of carbon dioxide produced in the reaction,

0.7 L propane × (3 liters Carbon Dioxide / 1 liter Propane) = 2.1 Liters of Carbon Dioxide

• 0.7 L propane × (4 liter water vapor / 1 liter propane ) = 2.8 Liters of Water Vapor

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3 years ago
Is it easy for gallium to change from solid to liquid? Why<br> subject is science
Alekssandra [29.7K]

Answer:

Solid gallium is a blue-gray metal with orthorhombic crystalline structure; very pure gallium has a stunning silvery color. Gallium is solid at normal room temperatures, but as well as mercury, cesium, and rubidium it becomes liquid when heated slightly

Explanation:

gallium is like water it freezes to turn solid!

...or like Bruce lee get it?

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3 years ago
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NISA [10]

Answer:

Explanation:

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Third STEP: The sodium (from NaNH₂ formed) transfers an electron again to produce a vinyl carbanion.

Fourth STEP: The carbanion then removes a proton/hydrogen from ammonia (like in the second step) to form a neutral trans-alkene.

NOTE: The circled numbers denote each step while the mechanism on the left represents the use of any alkyl group (R and R') while the mechanism on the right assumes both alkyl groups are methyl. Hence, 2-butyne started the reaction and the final product was trans-2-butene.

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Answer:

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