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Juliette [100K]
3 years ago
7

7.8g of dioxide would be produced from how many moles of potassium chlorate

Chemistry
1 answer:
Ghella [55]3 years ago
6 0
2KClO₃ ⇒ 2KCl + 3O₂
2mol         :            3mol
245,1g      :           95,94g
x               :           7,8g

x = 7,8g*245,1g / 95,94g = 19,93g

1mol of KClO₃ --------- is --------- 122,55g
x mol               --------- is --------- 19,93g

x = 19,93g*1mol / 122,55g = 0,158mol
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Find the fugacity coefficient of a gaseous species of mole fraction 0.4 and fugacity 25 psia in a mixture at a total pressure of
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<u>Answer:</u> The fugacity coefficient of a gaseous species is 1.25

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Fugacity coefficient is defined as the ratio of fugacity and the partial pressure of the gas. It is expressed as \bar{\phi}

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\bar{\phi}_i=\frac{\bar{f_i}}{p_i}

Partial pressure of the gas is expressed as:

p_i=\chi_iP

Putting this expression is above equation, we get:

\bar{\phi}_i=\frac{\bar{f_i}}{\chi_iP}

where,

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P = total pressure = 50 psia

Putting values in above equation, we get:

\bar{\phi}_i=\frac{25}{0.4\times 50}\\\\\bar{\phi}_i=1.25

Hence, the fugacity coefficient of a gaseous species is 1.25

8 0
3 years ago
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