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Juliette [100K]
3 years ago
7

7.8g of dioxide would be produced from how many moles of potassium chlorate

Chemistry
1 answer:
Ghella [55]3 years ago
6 0
2KClO₃ ⇒ 2KCl + 3O₂
2mol         :            3mol
245,1g      :           95,94g
x               :           7,8g

x = 7,8g*245,1g / 95,94g = 19,93g

1mol of KClO₃ --------- is --------- 122,55g
x mol               --------- is --------- 19,93g

x = 19,93g*1mol / 122,55g = 0,158mol
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