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Tcecarenko [31]
3 years ago
6

Find the greatest common factor of these three expressions. 18y4, 30y3, and 42y5

Mathematics
2 answers:
Alona [7]3 years ago
5 0

Answer:

6y³

Step-by-step explanation:

All three numbers are divisible by 6 and by y³

Leaving you with 3y, 5, and 7y²

Lapatulllka [165]3 years ago
3 0
6y^3 is the answer to the problem
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Explain how to draw a circle with a circumference of π2 inches. OPTIONS : The circle has a diameter of π2 inches, so use a diame
WINSTONCH [101]

Answer:

he circle has a radius of π inches, so use a radius of about 3.1 inches.

Step-by-step explanation:

The circumference of a circle can be described as the linear distance round the circle

The circumference of a circle = 2nr

n = 3.14

r = radius

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

diameter = 2r

If diameter = n2

diameter = 3.14 x 2 = 6.28

Radius = 1/2 x diameter = 6.28/2 = 3.1

4 0
3 years ago
The exchange rate at the Post Office is $1 = (1.17<br><br> How many euros will you get for E280?
nika2105 [10]

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Step-by-step explanation:

7 0
3 years ago
Find the complex conjugate of the given number -1+4i
adell [148]
With every imaginary term, there are 2 complex conjugates with opposing signs. So if I had the term a+bi, the complex conjugate would be a-bi. So given your example of -1+4i, the complex conjugate would just be the opposite sign, now negative, to get -1-4i.
3 0
3 years ago
Find the mount of simple interest on a 1800$ loan at 6% for 3 years
Arada [10]

Answer:

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Step-by-step explanation:

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3 0
4 years ago
De moirve's <br> (√3-i ÷ √3+i)^6 = 1
bulgar [2K]

(√3 - <em>i </em>) / (√3 + <em>i</em> ) × (√3 - <em>i</em> ) / (√3 - <em>i</em> ) = (√3 - <em>i</em> )² / ((√3)² - <em>i</em> ²)

… = ((√3)² - 2√3 <em>i</em> + <em>i</em> ²) / (3 - <em>i</em> ²)

… = (3 - 2√3 <em>i</em> - 1) / (3 - (-1))

… = (2 - 2√3 <em>i</em> ) / 4

… = 1/2 - √3/2 <em>i</em>

… = √((1/2)² + (-√3/2)²) exp(<em>i</em> arctan((-√3/2)/(1/2))

… = exp(<em>i</em> arctan(-√3))

… = exp(-<em>i</em> arctan(√3))

… = exp(-<em>iπ</em>/3)

By DeMoivre's theorem,

[(√3 - <em>i </em>) / (√3 + <em>i</em> )]⁶ = exp(-6<em>iπ</em>/3) = exp(-2<em>iπ</em>) = 1

7 0
3 years ago
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