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Llana [10]
3 years ago
10

A Canyon ball is fired from the ground level in angle of 35 from the ground at a speed of 150 m/s ignore air resistance calculat

e the horizontal and vertical components of its initial velocity
Physics
1 answer:
Virty [35]3 years ago
7 0

The velocity, 50 m/s, has two components - vertical and horizontal velocities.

The vertical component = 50 sin 30 = 25 m/s

The horizontal component = 50 cos 30 = 43.3 m/s

(a)  Let t be the time taken for the vertical component to reach its peak from initial velocity = 25 m/s to its final velocity = 0.

     Using the linear motion equation v = u - gt

     0 = 25 - 10t

     t = 2.5 s

    Time taken to go up and down = 5 s

    Time to hit the ground = 5 s

(b) Horizontal distance dealt x = 43.3 * 5 = 216.5 m

This is not the correct answer, but explains the problem thoroughly.

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3 years ago
Consider blood (density 1025 kg/m3) flowing through an artery with circular cross section that looks like this: Ignore viscosity
Klio2033 [76]

The given question is incomplete. The complete question is attached with an image below.

Explanation:

Mass flow rate through region A will be calculated as follows.

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8 0
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A 20.00-ohm, 5.00-watt resistor is placed in series with a power supply.(a) What is the maximum voltage that can be applied to t
Nutka1998 [239]
<h2>Answer:</h2>

(a) 10.00V

(b) 0.5V

<h2>Explanation:</h2>

(a) The power(P) supplied by a resistor of resistance (R) when a voltage(V) is passed across is given by;

P = V² / R       ------------------(i)

From the question;

P = 5.00W

R = 20.00Ω

Substitute these values into equation (i) as follows;

5.00 = V² / 20.00

V² = 5.00 x 20.00

V² = 100.00

V = \sqrt{100.00}

Solve for V;

V = 10.00V

Therefore, the maximum voltage that can be applied without harming the resistor is 10.00V

(b) By Ohm's law the current (I) flowing through a resistor of resistance (R) when a voltage (V) is applied is given by;

V = I x R

=> I = V / R             ----------------(ii)

Substitute the values of V and R into equation (ii) as follows;

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Therefore, the current through the resistor is 0.5A

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