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3 years ago

If a net force of 20 N is applied to a mass of 4kg, what is the acceleration

Physics

1 answer:

Wittaler [7]3 years ago

5 0

Answer:

I believe the answer is 16.404.

Explanation:

I used a calculator.

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Joe runs 10 m north, 20 m south, 9m south, and then 15 m north. What is Joe's<br> displacement?

tresset_1 [31]

Answer:

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2 years ago

If a car is accelerating downhill under a net force 3674 N , what additional force would cause the car to have a constant veloci

Semenov [28]

Answer:

For the car to move with constant velocity the additional force required is $F__{dg} }= -3674 \ N$

Explanation:

From the question we are told that

The net force of the car is $F_{net} = 3674 \ N$

Generally the total force acting on the car is the net force plus the force due to gravity acting in direction of the car (Let denote it as $F__{dg}$ )

So the total force acting on the car is mathematically represented as

$F_{net} + F__{dg}} = F$

Here this F representing the total force can be mathematically represented as

$F = ma$

Now for constant velocity to be attained, the acceleration of the car will be zero

So at constant velocity

$F = m * 0$

=> $F = 0 \ N$

$F_{net} + F__{dg}} = 0$

=> $F__{dg} }= -F_{net}$

=> $F__{dg} }= -3674 \ N$

6 0

3 years ago

Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

kramer

Answer:

$v_x = -6\ m/s$

Explanation:

initial velocity

magnitude of velocity, v = 12 m/s

angle made of velocity with negative x-axis,θ = 60°

We need to calculate x- component of v

$v_x = v cos \theta$

velocity is in negative x-direction, v = -12 m/s

now,

$v_x = -12\times cos 60^0$

$v_x = -12\times 0.5$

$v_x = -6\ m/s$

Hence, the velocity x-component is equal to -6 m/s.

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3 years ago

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2 years ago

If a net force of 20 N is applied to a mass of 4kg, what is the acceleration​

If a net force of 20 N is applied to a mass of 4kg, what is the acceleration