Answer:
a = v^2/r centripetal acceleration
v = (a * r)^1/2 = (42 * .23)^1/2 = 3.1 m/s
It would be B, the weather patterns outside.
<h2>
Answer:0.048</h2>
Explanation:
Let the length of perihelion be 
Let the length of aphelion be 
Let the length of semi major axis of the elliptical path be 
As we know that semi major axis is the average of perihelion and aphelion.
So,

Let the eccentricity of the elliptical path be 
