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LuckyWell [14K]
3 years ago
8

What is another unit for momentum besides kg-m/s? a. N b. N-s c. N-s2 d. N/s

Physics
1 answer:
lara [203]3 years ago
8 0
'Newton-second' is dimensionally equivalent to 'kilogram-meter/second'.
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In which situations is gravitational potential energy present?
Assoli18 [71]
Gravitational potential energy is associated with the shape or position of an object.
1.)When an object is placed at height h above ground, gravitational potential energy associated with it is given by,
P.E = mgh
2.)In projectile motion during upward motion, kinetic energy of object is converted into potential energy. 

6 0
3 years ago
How does the Earth release energy back into the atmosphere?
JulsSmile [24]

In general, the Earth releases energy back to the atmosphere through reflection, evaporation, and radiation. The Earth gets energy from the sunlight, part of which it absorbs, while part it reflects backwards, thus giving energy to the atmosphere. Also, the heating up of the Earth by the absorbed sunlight, radiates back in the lower layers of the atmosphere, again giving back energy to it. The water vapor is another way in which the Earth gives back energy tot he atmosphere as through the evaporation, the water vapor gets into the lower parts of the atmosphere and gives energy to it.

8 0
3 years ago
Suppose that a uniform electric field exists in a certain region of space. Now consider a mathematical plane surface of area A.
____ [38]

Answer: The normal of the plane must be parallel to the electric field vector.

Explanation:

the normal to the surface is defined as a versor that is perpendicular to the plane.

Now, if the angle between this normal and the line of the field is θ, we have that the flux can be written as:

Φ = E*A*cos(θ)

Where E is the field, A is the area and θ is the angle already defined.

Now, this maximizes when θ = 0.

This means that the normal of the surface must be parallel to the electric field

7 0
3 years ago
A lightening bolt may carry a current of 11800 A for a short period of time. The permeability of free space is 1.25664 × 10−6 T
Deffense [45]

Answer:

The resulting magnetic field is 5.021 x 10⁻⁵ T

Explanation:

Given;

current in the lightening bolt, I = 11800 A

distance from the bolt, r = 47 m

permeability of free space, μ₀ = 1.25664 × 10⁻⁶ T· m/A

Assume lightening bolt as long straight conductor, then the resulting magnetic field will be calculated as follows;

B = \frac{\mu_oI}{2 \pi r}

where;

B is the resulting magnetic field

I is the current in the bolt

r is the distance from the bolt

Substitute the given values and calculate B

B = \frac{\mu_oI}{2 \pi r} \\\\B = \frac{1.25664 *10^{-6}*11800}{2 \pi (47)} \\\\B = 5.021 *10^{-5} \ T

Thus, the resulting magnetic field is 5.021 x 10⁻⁵ T

4 0
3 years ago
A tennis ball has a mass of 0.058 kg and is moving to the right at 40 m/s. What is the momentum
Arte-miy333 [17]

Explanation:

Mass = 0.058Kg

Velocity = 40m/s

Momentum P = ?

P = mv

P = 0.058 × 40

P = 2.32Kgm/s

4 0
3 years ago
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