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hjlf
3 years ago
6

Use the rational exponent property to write an equivalent expression for

Mathematics
1 answer:
12345 [234]3 years ago
3 0

Answer:

i need to know what for

Step-by-step explanation:

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Jack and Jill both begin working new jobs for the summer. Jack is offered $18 per hour and will also be given $699 up front for
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349.5

Step-by-step explanation:

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What is the slope of (0,-1) and (5,-5)
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Find the measure of the indicated angle to the nearest degree.
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fiasKO [112]

4. The point Z is the orthocenter of the triangle.

5. The length of GZ is of 9 units.

6. The length of OT is of 9.6 units.

<h3>What is the orthocenter of a triangle?</h3>

The orthocenter of a triangle is the point of intersection of the three altitude lines of the triangle.

Hence, from the triangle given in the end of the answer, point Z is the orthocenter of the triangle.

For the midpoints connected through the orthocenter, the orthocenter is the midpoint of these segments, hence:

  • The length of segment GZ is obtained as follows: GZ = 0.5 GU = 9 units. -> As z is the midpoint of the segment.
  • The length of segment OT is obtained as follows: OT = 2ZT = 2 x 4.8 = 9.6 units.

<h3>Missing Information</h3>

The complete problem is given by the image at the end of the answer.

More can be learned about the orthocenter of a triangle at brainly.com/question/1597286

#SPJ1

8 0
1 year ago
What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?
Trava [24]

Answer:

\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}

Step-by-step explanation:

The explicit formula for a geometric sequence:

a_n=a_1r^{n-1}

a_n - n-th term

a_1 - first term

r - common ratio

r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}

We have

a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...

The common ratio:

r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}

<h2>It's not a geometric sequence.</h2>

If a_3=-\dfrac{1}{16} then the common ratio is r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}

Put to the explicit formula:

a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}

Put a_n=\dfrac{1}{1024} and solve for <em>n </em>:

-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1

\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6

5 0
3 years ago
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