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3 years ago

Solve the system of equations by substitution y = 2x + 1 and 3x + y = 16

Mathematics

1 answer:

Luden [163]3 years ago

6 0

Answer: y=7,x=3

Steps:

y = 2x + 1

3x + y = 16

Substitute y = 2x + 1

3x + 2x + 1 = 16

Simplify

5x+1=16

Isolate x for 5x + 1 = 16: x = 3

For y = 2x + 1

Substitute x = 3

y = 2 · 3 + 1

Simplify

y = 7

The solutions to the system of equations are:

y = 7, x = 3

Hope This Helps!

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my sister and I ate some of a chocolate bar. she ate 3/5 of it and I ate 1/10 of it. how much of the chocolate bar did we eat

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Given: F(x) = x + 2 and G(x) = 3x + 5<br><br> (F*G) (x) =

vovangra [49]

Answer:

$\boxed{(f \times g)(x) = 3 {x}^{2} + 11x + 10}$

Given:

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To Find:

$(f \times g)(x) = f(x) \times g(x)$

Step-by-step explanation:

$= > f(x) \times g(x) = (x + 2)( 3x + 5) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =x( 3x + 5) + 2(3x + 5) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =3 {x}^{2} + 5x + 6x + 10\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =3 {x}^{2} + 11x + 10$

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For what value of "a" will the product shown below have a purely imaginary value? (Show work please)

MakcuM [25]

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The -10 comes from 5i * 2i.
Squaring i becomes -1.

Let's group the real stuff together,
and imaginary separately,

(4a - 10) + (5a + 8)i

For this to be purely imaginary,
the real part needs to be zero.

Therefore 4a - 10 = 0

Solve for a.

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3 years ago