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Andrej [43]
3 years ago
8

Solve the system of equations by substitution y = 2x + 1 and 3x + y = 16

Mathematics
1 answer:
Luden [163]3 years ago
6 0

Answer:  y=7,x=3

Steps:

y = 2x + 1

3x + y = 16

Substitute y = 2x + 1

3x + 2x + 1 = 16

Simplify

5x+1=16

Isolate x for 5x + 1 = 16: x = 3

For y = 2x + 1

Substitute x = 3

y = 2 · 3 + 1

Simplify

y = 7

The solutions to the system of equations are:

y = 7, x = 3

Hope This Helps!

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3 years ago
The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c
valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is 10.4 \:cm^2

Step-by-step explanation:

The area of a rectangle with length L and width W is A= L\cdot W so the differential of <em>A</em> is

dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W

\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L so

dA=W\Delta L+L \Delta W

We know that each error is at most 0.1 cm, we have |\Delta L|\leq 0.1, |\Delta W|\leq 0.1. To find the maximum error in the calculated area of the rectangle we take \Delta L = 0.1, \Delta W = 0.1 and L=55, W=49. This gives

dA=49\cdot 0.1+55 \cdot 0.1

dA=10.4

Thus the maximum error in the calculated area of the rectangle is 10.4 \:cm^2

4 0
3 years ago
Need a quick answer please
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39

Step-by-step explanation:

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Marj needs to round $345.67$, and she wants the result to be as large as possible. She has to round to the nearest thousand, the
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3x-2=x+10 help please
pav-90 [236]
3x-x=10+2
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3 years ago
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