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kenny6666 [7]
3 years ago
5

Divide . 1 1/2 by 2 1/2

Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0

Answer:

0.6. That's the Answer sir


Step by Step Explaining:

None.


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Evan's science class placed some metal balls on a scale. They used a red ball that weighed 5/13 of a pound, a yellow ball that w
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Answer:

2 4/221 = 2.018

Step-by-step explanation:

5/13+10/17+5/13+4/13+6/17 = 2 4/221 = 2.018

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Rewarding brainly and if you dont look for a unanswered question i posted or lmk if you want me to post one (NOT THIS ONE)
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Step-by-step explanation:

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3 years ago
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Please help(ik it’s not c)
Talja [164]
The answer is A. 45 degrees
6 0
2 years ago
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Y = –3x + 5 y = mx + b Which values of m and b will create a system of linear equations with no solution? m = –3 and b = –3 m =
beks73 [17]

Answer:

(A) m = –3 and b = –3

Step-by-step explanation:

If m=–3 and b=–3

The system of linear equations:

y = –3x + 5

y = mx + b

Becomes

y = –3x + 5 ......(i)

y = –3x – 3   .......(ii)

Notice that 5 is added to -3x in (i) and -3 is added to -3x in (ii) and both equals y. This is impossible. Thus the system has no solution.

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3 years ago
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Tom determines that the system of equations below has two solutions, one of which is located at the vertex of the parabola.
xxTIMURxx [149]

Answer:

Option A: b must equal 7 and a second solution to the system must be located at the point (2, 5)

Step-by-step explanation:

<u><em>The complete question is</em></u>

Tom determines that the system of equations below has two solutions, one of which is located at the vertex of the parabola.

Equation 1: (x – 3)2 = y – 4

Equation 2: y = -x + b

In order for Tom’s thinking to be correct, which qualifications must be met?

A: b must equal 7 and a second solution to the system must be located at the point (2, 5).

B: b must equal 1 and a second solution to the system must be located at the point (4, 5).

C: b must equal 7 and a second solution to the system must be located at the point (1, 8).

D: b must equal 1 and a second solution to the system must be located at the point (3, 4).

step 1

Find the vertex of the quadratic equation

The general equation of a vertical parabola in vertex form is

y=a(x-h)^2+k

where

(h,k) is the vertex

we have

(x-3)^{2}=y-4

so

y=(x-3)^{2}+4

The vertex is the point (3,4)

step 2

Find out the value of b in the linear equation

we know that

If the vertex is a solution of the system of equations, then the vertex must satisfy both equations

substitute the value of x and the value of y of the vertex in the linear equation

y=-x+b

For x=3, y=4

4=-3+b\\b=7

so

y=-x+7

step 3

Find out the second solution of the system of equations

we have

y=(x-3)^{2}+4 -----> equation A

y=-x+7 ----> equation B

solve the system of equations by graphing

Remember that the solutions are the intersection points both graphs

The second solution of the system of equations is (2,5)

see the attached figure

therefore

b must equal 7 and a second solution to the system must be located at the point (2, 5)

5 0
3 years ago
Read 2 more answers
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