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Lunna [17]
3 years ago
9

The name of a .java file should ______________________________. Always match the name of the Class inside Should always start wi

th a capital letter for compilation Should always be changed after compilation to prevent bytecode conflicts Always start with a lowercase letter for compilation
Computers and Technology
1 answer:
natita [175]3 years ago
7 0

Answer:

The name of a .java file should <u>always match the name of the class inside.</u>

Explanation:

In Java programming the program written in code editor is first saved with .java extension. The name of this .java file should be same as that of  the class declared inside the file.

This .java file is then compiled and  converted to .class file which contains the java bytecode. This bytecode can then be executed by java virtual machine(JVM).

However it is not always necessary that name of .java files should be same as that of class inside it. The name should be same only when the class inside is declared as public.

In case it is not declared as public one can name .java file different than the actual class name.  

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Answer:

The following program are written in JAVA Programming Language.

//inherit the Calculator class

public class CalculatorWithMemory extends Calculator {  

   private double memory = 0.0;    //initialize double type variable

   public void save() {   //define function

       memory = accumulator;    

   }

   public void recall() {   //define function

       accumulator = memory;

   }

   public void clearMemory() {   //define function

       memory = 0;     //initialize the value

   }

   public double getMemory() {  

       return memory;    // return the value in "memory" variable

   }

}

Explanation:

Here, we inherit the property of the "Calculator" class.

Then, we define the private double type variable "memory" and assign value 0.0.

Then we set the function "save()" inside it we assign the value of "memory" in "accumulator" and close the function.

Then, we define the function "recall()" inside it we assign the value of "accumulator" in "memory" and close the function.

Then we set the function "clearMemory()" inside it we assign "memory" to 0.

After all, we set the double type function "getMemory()" inside we return the value of the "memory".

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4 years ago
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Explanation:

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Explanation:

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Answer:

int x;

indata.open("lottowins");

indata >> x;

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indata >> x;

cout << x << endl;

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indata.close();

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