Question

Write an equation of a line that passes through the point (5,1) and is parallel to the line y= (-3/5)x -3

Answer 1

Answer:

y = (-3/5)x + 4

Step-by-step explanation:

Parallel lines have the same slope.

So the slope to the other line would be -3/5 as well.

Slope-intercept form is y = mx + b where m is the slope.

So you substitute the slope in making it y = (-3/5)x+b.

To find b, the y-intercept, you have to plug in the point for y and x in it. So you use the point (5,1) for it. That would get to 1 = (-3/5)5 + b.

To simplify that, it would get to 1 = -3 + b

Then you add 3 on both sides getting to b = 4.

Then you substitute b in, getting y = (-3/5)x + 4.

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