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Pavel [41]
2 years ago
12

The χ2 value means nothing on its own--it is used to find the probability that, assuming the hypothesis is true, the observed da

ta set could have resulted from random fluctuations. A low probability suggests the observed data is not consistent with the hypothesis, and thus the hypothesis should be rejected. What is the hypothesis that you are testing?
A) The two genes are unlinked and are assorting independently, leading to a 1:1:1:1 ratio of phenotypes in the offspring.
B) The two genes are unlinked and are assorting independently, leading to a 1:1:0:0 ratio of phenotypes in the offspring.
C) The two genes are linked and are assorting together, leading to a 1:1:1:1 ratio of phenotypes in the offspring.
D) The two genes are linked and are assorting together, leading to a ratio of phenotypes in the offspring that deviates significantly from 1:1:1:1.
Biology
1 answer:
vova2212 [387]2 years ago
4 0

Answer:

A) The two genes are unlinked and are assorting independently, leading to a 1:1:1:1 ratio of phenotypes in the offspring.

Explanation:

The χ2 value means nothing on its own--it is used to find the probability that, assuming the hypothesis is true, the observed data set could have resulted from random fluctuations. A low probability suggests the observed data is not consistent with the hypothesis, and thus the hypothesis should be rejected. The hypothesis that you are testing are two genes are unlinked and are assorting independently, leading to a 1:1:1:1 ratio of phenotypes in the offspring.

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5 0
2 years ago
The length of linker DNA segments varies somewhat among organisms. The length of the linker DNA in sea urchin is 110 base pairs.
nasty-shy [4]

Answer:

362 nucleosomes

Explanation:

A nucleosome repeat is made up of the DNA (146 bp) wrapped around the core nucleosome particle and the linker DNA (110 bp as in this situation). We can conclude that, every repeat stands for 256 (146 + 110) base pairs of DNA.

We are given the length of the entire region to be 92,672 bp long,

To determine the number of nucleosomes to organize the region into the 10nm fiber structure

Let,

Number of nucleosomes =

the length of the entire region

------------------- -----

base pairs of DNA.

= 92,672

-------

256

= 362 nucleosomes

Therefore, 362 nucleosomes is needed to structure the region into the 10nm fiber structure.

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