The value of h(t) when
is 10.02.
Solution:
Given function 
To find the value of h(t) when
:

Substitute
in the given function.


Now multiply the common terms into inside the bracket.

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

To make the denominator same, take LCM of the denominators.
LCM of 64 and 32 = 64




= 10.02

Hence the value of h(t) when
is 10.02.
Well 42 divided by 2 is 21. than to double check you can do 21 plus 21 equals 42.
Answer: 1/4
Step-by-step explanation:
In a stack of 24, the 2 mediums are odd and even cards in this question. This means that 1/2 the cards are even and 1/2 are odd. To get a even card once is a 1/2 chance, then to get it again is 1/2 x 1/2 chance or 1/4 chance. This is what I think.
C ≈ 307.88
Hope that helps.