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2 years ago

What is the value of x? A.39B.41C.26D.17

Mathematics

1 answer:

mojhsa [17]2 years ago

3 0

Answer:

The answer is B.

Step-by-step explanation:

You have to use Pythogorean Theorem, c² = a² + b² where c is the hypotenuse and a,b is the side lengths :

${c}^{2} = {a}^{2} + {b}^{2}$

Let a = 40,

Let b = 9,

${c}^{2} = {40}^{2} + {9}^{2}$

${c}^{2} = 1600 + 81$

${c}^{2} = 1681$

$c = \sqrt{1681}$

$c = 41 \: units$

*Take note, hypotenuse will always be the longest length among the 3 lengths.

*Pythogorean Theorem can only applied in a right-angle triangle.

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3 years ago

If a = b and b = c, which statement must be true?

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3 years ago

What is the slope-intercept form of the equation of the line that passes through the points (−3, 2) and (1, 5)?

IceJOKER [234]

Answer:

y = 3/4x + 17/4

Step-by-step explanation:

Step 1: Find slope m

m = (5 - 2)/(1 + 3)

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Step 2: Find b

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3 years ago

Read 2 more answers

URGET PLEASE HELP QUICKLY

alexdok [17]

Answer: -0.5.

Step-by-step explanation:

The constant of variation k for the direct variation is given by:-

$k= \dfrac{f(x_2)}{x_2}=\dfrac{f(x_1)}{x_1}$

The given table:

x f( x )

0 0

2 -1

4 -2

7 -3.5

Then,

$k=\dfrac{-1}{2}=\dfrac{-2}{4}=\dfrac{7}{-3.5}=-0.5$

Hence, the constant of variation k for the direct variation is -0.5.

4 0

3 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

What is the value of x? A.39B.41C.26D.17​

What is the value of x? A.39B.41C.26D.17