No, because the word might offend that person.
Answer:
20 ohms,100*2/10=20
Explanation:
since it as to be in parallel arrangement and connected in side by side due to same p.d in a cross each resistor
<span>
No. of e- at a instant through given area is = total charge passing per
unit time/charge of e-
using i=q/t=(no.of e-(n))(1.6*10^-19)= 10
n=6.3*10^19 </span>
Answer:
No
Explanation:
The vertical component of Jack's initial velocity is:
5.0
⋅
sin
30
∘
=
5.0
⋅
1
2
=
2.5
m/s
With gravitational acceleration
9.8
m/s
2
, he will reach the highest point of his trajectory after:
2.5
9.8
≈
0.255
s
The average vertical component of his velocity in that
0.255
s
will be:
1
2
⋅
2.5
=
1.25
m/s
So the highest point of his trajectory will be:
0.255
⋅
1.25
≈
0.32
m
So he will pass approximately
7
cm
above the top of the candle.
The horizontal component of his velocity will be a constant:
5.0
⋅
cos
30
∘
=
5.0
⋅
√
3
2
≈
4.33
m/s
So Jack's trajectory will be substantially longer than it is high and he will spend little time anywhere near above the candle.
