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Firdavs [7]
3 years ago
13

Rutherford proposed that

Physics
1 answer:
Mila [183]3 years ago
4 0

The answer is C. Because Rutherford purposed that negatively charged electrons orbit a positively charged nucleus in orbits with set energy levels.

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What is the speed of the 5 states of matter?
dexar [7]
Solid, liquid, gas, and plasma. hope that helped
4 0
3 years ago
Answers please!!!!!!!!!!!!!!!!
kaheart [24]
I only know #2 and #4.
2.) cells
3.) cells,  life , existing

Sorry that i dont know the rest but i took a test on this not to long ago, and i tend to forget stuff once i take a test on it.


3 0
4 years ago
Water drops fall from the edge of a roof at a steady rate. a fifth drop starts to fall just as the first drop hits the ground. a
Alchen [17]

The height of the roof is <u>3.57m</u>

Let the drops fall at a rate of 1 drop per t seconds. The first drop takes 5t seconds to reach the ground. The second drop takes 4t seconds to reach the bottom of the 1.00 m window, while the 3rd drop takes 3t s to reach the top of the window.

Calculate the distances traveled by the second and the third drops s₂ and s₃, which start from rest from the roof of the building.

s_2=\frac{1}{2} g(4t)^2=8gt^2\\  s_3=\frac{1}{2} g(3t)^2=(4.5)gt^2

The length of the window s is given by,

s=s_2-s_3\\ (1.00 m)=8gt^2-4.5gt^2=3.5gt^2\\ t^2=\frac{1.00 m}{(3.5)(9.8m/s^2)} =0.02915s^2

The first drop is at the bottom and it takes 5t seconds to reach down.

The height of the roof h is the distance traveled by the first drop and is given by,

h=\frac{1}{2} g(5t)^2=\frac{25t^2}{2g} =\frac{25(0.02915s^2)}{2(9.8m/s^2)} =3.57 m

the height of the roof is 3.57 m



8 0
4 years ago
Read 2 more answers
A wave with a large amplitude has a lot of             a.vibration  b.speed   c.energy    
adoni [48]
<span>A wave with a large amplitude has a lot of             a.vibration  b.speed  <u> c.energy</u></span>
6 0
3 years ago
Read 2 more answers
A truck initially traveling at 20m/s decelerated at 1.50m/s2. Find (a) how long it takes to stop (b) how far it moves in that ti
finlep [7]

vf² = vi² + 2ad

vf = vi +at

vf = final velocity

vi = initial velocity

decelerated = a = - (negative)

a. stop ⇒ vf = 0

vf = vi+at

0 = 20 - 1.5t

1.5t=20

t = 13.3 s

b. vi = 20 m/s

0 = 20² - 1.5d

1.5d = 20²

1.5d = 400

d =266.67 m

c. d = vi.t -1/2at²

d = 20.3 - 1/2.1.5.3²

d = 53.25 m

5 0
3 years ago
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