All categories

3 years ago

Rutherford proposed that

1 answer:

4 0

The answer is C. Because Rutherford purposed that negatively charged electrons orbit a positively charged nucleus in orbits with set energy levels.

You might be interested in

A soccerball is kicked straight out from a hill at 15 m/s and lands 42m away. how tall is the hill

ozzi

Answer:

The height of the hill is, h = 38.42 m

Explanation:

Given,

The horizontal velocity of the soccer ball, Vx = 15 m/s

The range of the soccer ball, s = 42 m

The projectile projected from a height is given by the formula

S = Vx [Vy + √(Vy² + 2gh)] / g

Therefore,

h = S²g/2Vx² (Since Vy = 0)

Substituting the values

h = 42² x 9.8/ (2 x 15²)

= 38.42 m

Hence, the height of the hill is, h = 38.42 m

4 0

2 years ago

Samantha is viewing a real image formed by a lens of a diamond ring. Which must be true about the image?

Ad libitum [116K]

<span>It could not be captured on film. is the answer</span>

4 0

2 years ago

Read 2 more answers

The moon is 3.85 x 10 to the 8 m from earth and has a diameter of 3.48 x 10 to the 6 m. You have a pea (diameter = 0.50 cm) and

polet [3.4K]

Answer:

(a) dime

Explanation:

Convert all to metric unit:

0.5 cm = 0.005 m

1.8 cm = 0.018 m

71 cm = 0.71 m

In order to find out we would need to calculate the ratio R between the object diameter d and their distance s to our eyes:

$R_m = \frac{d_m}{s_m} = \frac{3.48*10^6}{3.85*10^8} \approx 0.009$

$R_p = \frac{d_p}{s_p} = \frac{0.005}{0.71} \approx 0.007$

$R_d = \frac{d_d}{s_d} = \frac{0.018}{0.71} \approx 0.0253$

Since the ratio of the dime is larger than the ratio of the moon, and the ratio of the pea is smaller than the ratio of the moon, only the (a) dime can cover your view of the moon.

3 0

3 years ago

Electromagnetic induction is the production of a voltage across a conductor when it is exposed to a varying magnetic field. This

Darina [25.2K]

Answer:

D) Electric power distribution.

Explanation:

Electric power distribution requires high voltages to efficiently transmit electric power. This requires use of a transformer which uses electromagnetic induction.

6 0

2 years ago

Read 2 more answers

What is the highest energy photon that can be absorbed by a ground-state hydrogen atom without causing ionization?

lakkis [162]

Highest energy photon absorbed: $2.18\cdot 10^{-18}J$

Explanation:

An atom is said to be (positively) ionised when it absorbs a photon, and as a consequence, an electron becomes energetic enough to escape the atom, leaving an excess of positive charge behind.

In order for the electron to escape, the energy of the absorbed photon must be exactly equal to the (negative) energy of the level in which the electron lies.

For an hydrogen atom, the energy levels are given by

$E_n = -13.6 \frac{1}{n^2}$

where this energy is measured in electronvolts, and n is the number of the energy level.

Since the energy is negative, this means that the electron which requires most energy is the one lying in the ground state (n=1). Therefore, for an electron in the ground state, the most energy that can be absorbed from the incoming photon is

$E_1 = -13.6 eV$

Converting into Joules, this is equal to

$E_1 = 13.6 \cdot 1.6\cdot 10^{-19}=2.18\cdot 10^{-18}J$

Learn more about hydrogen atom:

brainly.com/question/2757829

#LearnwithBrainly

3 0

3 years ago