<span>The 2nd truck was overloaded with a load of 16833 kg instead of the permissible load of 8000 kg.
The key here is the conservation of momentum.
For the first truck, the momentum is
0(5100 + 4300)
The second truck has a starting momentum of
60(5100 + x)
And finally, after the collision, the momentum of the whole system is
42(5100 + 4300 + 5100 + x)
So let's set the equations for before and after the collision equal to each other.
0(5100 + 4300) + 60(5100 + x) = 42(5100 + 4300 + 5100 + x)
And solve for x, first by adding the constant terms
0(5100 + 4300) + 60(5100 + x) = 42(14500 + x)
Getting rid of the zero term
60(5100 + x) = 42(14500 + x)
Distribute the 60 and the 42.
60*5100 + 60x = 42*14500 + 42x
306000 + 60x = 609000 + 42x
Subtract 42x from both sides
306000 + 18x = 609000
Subtract 306000 from both sides
18x = 303000
And divide both sides by 18
x = 16833.33
So we have the 2nd truck with a load of 16833.33 kg, which is well over it's maximum permissible load of 8000 kg. Let's verify the results by plugging that mass into the before and after collision momentums.
60(5100 + 16833.33) = 60(21933.33) = 1316000
42(5100 + 4300 + 5100 + 16833.33) = 42(31333.33) = 1316000
They match. The 2nd truck was definitely over loaded.</span>
Answer:
The ratio of the forces is F2/F1 = 1.86
Explanation:
From Newton's second law applied to circular motion, the total force F acting on a body in circular motion is given by
F = mv²/r
Where
m = mass of the body undergoing circular motion
v = linear velocity = ω×r
ω = angular velocity
r = radius of the circular path through which the force acts
So
F = m(ω×r)²/r = mω²×r
Given 2 angular speeds ω1 = 439re/min = 439×2π/60 rad/s = 46 rad/s and
ω2 = 602rev/min = 602×2π/60 rad/s = 63 rad/s
Required to calculate the ratio F2/F1
The mass m and radius r is the same for both forces, so F is dependent on the angular speed
So F2/F1 = ω2²/ω1² = (ω2/ω1)²
F2/F1 = (63/46)² = 1.86
Answer:
He should use 90 for Q3 ⇒ answer A
Explanation:
Lets explain the meaning of Q3
Q1 is the "middle" value in the first half of the data set
Q2 is the median value in the set
Q3 is the "middle" value in the second half of the data set
The data are
76 , 79 , 81 , 83 , 85 , 86 , 89 , 91 , 93
The set has nine numbers, then Q2 is the fifth one
Q2 = 85
The first half of the data are:
76 , 79 , 81 , 83
The second half of the data are:
86 , 89 , 91 , 93
They are four numbers, then the middle one is the average of the
second and the third numbers
Q3 =
<em>He should use 90 for Q3 </em>
Your question asks what a scientific law is.
Your answer would be B). What scientists expect will always happen under particular circumstances
A scientific law is something that will always happen, it is mostly like a repeat when doing a experiment with certain factors in place. This is also known as a "natural law" because something will naturally happen when it is enacted with the same factors for multiple "trials". This "scientific law" will allow scientist to predict what would happen during other multiple trials that are conducted. Concise data would be received from these trials.
An example of a scientific law is Newton's law of gravitation.
Therefore, your answer would be B.
Is where scientist easily handle very small numbers or very large numbers. It best that way.