Question

What are the approximate solutions of 2x2 − 7x = 3, rounded to the nearest hundredth?

Answer 1

2x^2 − 7x = 3

2x^2 - 7x -3 = 0

Use the quadratic formula:

$x = \frac{7+/- \sqrt{ 7^{2}-4(2)(-3)} }{(2)(2)} = [7+/-8.544]/4$

x =- 0.386 and x = 3.89

Answer option C: x = -0.39 and x = 3.89

Answer 2

Answer:

Option C is the correct option.

Step-by-step explanation:

The given equation is 2x² - 7x - 3 = 0

In this quadratic equation we will use quadratic formula to get the roots of x.

$x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

By putting values of a = 2, b = -7 and c = -3 in the quadratic formula

$x=\frac{7\pm \sqrt{(-7)^{2}-4\times 2\times (-3)}}{2\times 2}$

$=\frac{7\pm \sqrt{49+24}}{4}$

$=\frac{7\pm \sqrt{73}}{4}$

Now we get two values for x

$x=\frac{7+\sqrt{73}}{4}$

$=\frac{7+8.54}{4}=3.89$

and $x=\frac{7-\sqrt{73}}{4}$

$=\frac{7-8.54}{4}$

$=-\frac{1.54}{4}=-0.39$

Therefore option C. is the answer.