Answer:
The person would have to play 2 games for the two bowling alleys to cost the same amount
Step-by-step explanation:
Assume that the number of games that makes the two costs equal is x
∵ A bowling alley charges $2.50 per game plus $4 to rent shoes
∵ The number of games is x
∴ The cost = 2.50x + 4
∵ A second bowling alley charges $4 per game plus $1 to rent shoes
∵ The number of games is x
∴ The cost = 4x + 1
∵ They have the same cost
→ Equate the 2 expressions above
∴ 4x + 1 = 2.50x + 4
→ Subtract 2.50x from both sides
∵ 4x - 2.50x + 1 = 2.50x - 2.50x + 4
∴ 1.50x + 1 = 4
→ Subtract 1 from both sides
∵ 1.50x + 1 - 1 = 4 - 1
∴ 1.50x = 3
→ Divide both sides by 1.50
∴ x = 2
∴ The person would have to play 2 games for the two bowling alleys to
cost the same amount
The center is at origin O(0,0).
If it contains the point, P(-8,6), then the radius r is, by Pythagoras theorem,
r=sqrt((-8)^2+6^2)=10
The general equation of a circle at centre (xc,yc) with radius r is given by
(x-xc)^2+(y-yc)^2=r^2
Substituting r=10, (xc,yc)=(0,0)
the resulting equation is therefore
(x-0)^2+(y-0)^2=10^2
or simply
x^2+y^2=100
Answer:
(-65)/17
Step-by-step explanation:
Evaluate 3/(x - 2) - sqrt(x - 3) where x = 19:
3/(x - 2) - sqrt(x - 3) = 3/(19 - 2) - sqrt(19 - 3)
19 - 3 = 16:
3/(19 - 2) - sqrt(16)
19 - 2 = 17:
3/17 - sqrt(16)
sqrt(16) = sqrt(2^4) = 2^2:
3/17 - 2^2
2^2 = 4:
3/17 - 4
Put 3/17 - 4 over the common denominator 17. 3/17 - 4 = 3/17 + (17 (-4))/17:
3/17 - (4×17)/17
17 (-4) = -68:
3/17 + (-68)/17
3/17 - 68/17 = (3 - 68)/17:
(3 - 68)/17
3 - 68 = -65:
Answer: (-65)/17
5 x 6 is greater than 25.
( Hope this helps!! ) <3
