Slope=-9/12 = -3/4
y=mx+b y=-3/4x+b
3=-3/4(-6)+b
b=3+9/2=7.5
Equation is y=-0.75x+7.5
The sequence is, in fact, quadratic. It is described by the equation
.. a[n] = (n*(n -1))/2 +2
First differences are increasing, so the sequence will not be arithmetic. An arithmetic sequence has constant first differences.
Second differences are constant, so the sequence will not be geometric. A geometric sequence will have first-, second-, third-differences, and those to any level, that have the same constant ratio as the terms of the original sequence.
Answer:
x = 40
Step-by-step explanation:
Adding 23 to both sides gives us:
x - 23 + 23 = 17 + 23
x = 40
Answer:
this copy and paste is to hard to read making it impossible to solve sorry.
Step-by-step explanation:
Remember that the vertex form of a parabola or quadratic equation is:
y=a(x-h)^2+k, where (h,k) is the "vertex" which is the maximum or minimum point of the parabola (and a is half the acceleration of the of the function, but that is maybe too much :P)
In this case we are given that the vertex is (1,1) so we have:
y=a(x-1)^2+1, and then we are told that there is a point (0,-3) so we can say:
-3=a(0-1)^2+1
-3=a+1
-4=a so our complete equation in vertex form is:
y=-4(x-1)^2+1
Now you wish to know where the x-intercepts are. x-intercepts are when the graph touches the x-axis, ie, when y=0 so
0=-4(x-1)^2+1 add 4(x-1)^2 to both sides
4(x-1)^2=1 divide both sides by 4
(x-1)^2=1/4 take the square root of both sides
x-1=±√(1/4) which is equal to
x-1=±1/2 add 1 to both sides
x=1±1/2
So x=0.5 and 1.5, thus the x-intercept points are:
(0.5, 0) and (1.5, 0) or if you like fractions:
(1/2, 0) and (3/2, 0) :P
