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katen-ka-za [31]
3 years ago
9

What is the length of any side of equilateral triangle TUV? a. 7 b. 15 c. 20 d. 24

Mathematics
1 answer:
NikAS [45]3 years ago
6 0
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NEED ASAP plz. I will also mark brainiest! Don't just take points, I will report you.
PilotLPTM [1.2K]

Part A:

You may choose the two lines connecting the origin and points A and B, and choose the portion of the space between them.

The line between the origin and A is

y = 3x

We want everything below this line (line included), so the first inequality is

y \leq 3x

The line between the origin and B is

y = \dfrac{1}{3}x

We want everything above this line (line included), so the second inequality is

y \geq \dfrac{1}{3}x

Create a system with these two inequalities and you'll have an area including only points A and B

Part B:

To verify the solutions, we can plug the coordinates of A and B in this system and check that we get something true: the coordinates of point A are (1,3), while the coordinates of point B are (3,1). The system becomes:

A:\begin{cases}3 \leq 3\cdot 1\\3 \geq \frac{1}{3}\cdot 1\end{cases},\quad B:\begin{cases}1 \leq 3\cdot 3\\1 \geq \frac{1}{3}\cdot 3\end{cases}

Which means

A:\begin{cases}3 \leq 3\\3 \geq \frac{1}{3}\end{cases},\quad B:\begin{cases}1 \leq 9\\1 \geq 1\end{cases}

And these are all true. So, the system is satisfied, which means that the points belong to the shaded area.

Part C

If you draw the line, you'll see that the only points that lay below the line are B and C. In fact, if we plug the coordinates we have

B:\ 1

And this are both true. You can check the coordinates of all other points, and see that they won't satisfy the inequality y<3x-6

3 0
3 years ago
Threeangles of a quadrilateral are equal and its fourth angel is 120° . Find all the angels
lilavasa [31]

Answer:

80°

Step-by-step explanation:

Three angles are equal

Let the equal angle be x

3x+120=360

3x=240

x=240/3

=80

Hence the three angles are 80∘


6 0
3 years ago
Read 2 more answers
What is 28a^11 b^7 divided by 4a^3b
Veronika [31]
Reduce the expression<span> by cancelling the </span><span>common factors</span><span>.
</span><span><span>7<span>a^11</span><span>b^7/</span></span><span><span>a^3</span>b

</span></span>Reduce the expression<span> by cancelling the </span><span>common factors</span><span>.
</span><span>7<span>a^8</span><span>b^7/</span></span>b

Reduce the expression<span> by cancelling the </span><span>common factors</span><span>.
</span>7<span>a^8</span><span>b^<span>6



</span></span>28a^11 b^7 divided by 4a^3b simplified is 7a^8b^6
4 0
3 years ago
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Think of a trapezoid with b1 and b2 as the length of the bases, h as the length of the altitude, and A as the area. Find the mis
Marina86 [1]
Area = 1/2 x (sum of bases) x height
18 = 1/2 x (6 + b2) x 2
b2 = 12.
3 0
3 years ago
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Work out the circumfence of this circle
Anastaziya [24]

Answer:

C = πd = 14π = 14 * 3.142 = 43.988

6 0
3 years ago
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